Question

Is diphenylmethanol likely to be more or less polar than benzophenone? How might you test this.

Answer 1

Hint:We know that the compounds like biphenyl, benzhydrol, and benzophenone from which benzhydrol is alcohol so in short there is more polarity in it from others. Similarly benzophenone is a ketone in result it will have less polar than benzhydrol but will have more polar than biphenyl

Complete answer:
We can conclude answer on the basis of hydroxyl substituent here a strong POLAR is a functional group which are \[{{\left( {{C}_{6}}{{H}_{5}} \right)}_{2}}CHOH\] along with \[O=C{{\left( {{C}_{6}}{{H}_{5}} \right)}_{2}}\] and that to in the test for the polarity we have the result which is solubility of each compound in weakly polar solvents example diethyl ether as well as in strong polar solvent example ethanol.
Where a hydroxyl substituent plays a key role that a hydroxy or hydroxyl group is an entity with the formula $OH$ it has one oxygen bond to $1$ hydrogen. Similarly in organic chemistry, when alcohol and carboxylic acid are containing hydroxyl groups. Here both are negative charge anions \[O{{H}^{-}}\] and are called hydroxide as well as the neutral radical.
Thus, the given compounds in the order of their increasing compound polarity is given as
diphenylmethanol < benzophenone < benzhydrol*

Note: Note that dichloromethane has one of the best separation between out of two of them also it was not as clear as it should be. We can have the final result with toluene as solvent to the correspondent system. We have to select toluene because it was one of the most nonpolar out of all solvent that is why the most nonpolar solvent because the compounds in mixture are ranged from mostly nonpolar to extreme nonpolar.