Question

In the reaction$A + B \rightleftharpoons AB$, if the concentration of A and B is increased by a factor of 2, it will cause the equilibrium concentration of AB to change to.

Answer 1

Hint: We know that to compute an equilibrium fixation from a balance steady, a comprehension of the idea of balance and how to compose a balance consistent is required. Balance is a condition of dynamic equilibrium where the proportion of the item and reactant fixations is consistent.

Complete answer:
We must have to remember that in a synthetic response, when both the reactants and the items are in a focus which doesn't change with time any more, it is supposed to be in a condition of compound equilibrium. In this express, the pace of forward response is the same as the pace of reverse response. For a response, on the off chance that you know the underlying convergences of the substances, you can compute the equilibrium fixation.
We must have to know that the equilibrium happens for a reversible response. Reversible implies that as reactants find one another and become items, items in the long run collect and change upon themselves, responding to change reactants. Balance is arrived at when framework is not, at this point apparently evolving. That point isn't arrived at when there is an equivalent measure of items and reactants, yet rather when the rate at which items are made is equivalent to the rate at which reactants are made.
The balanced given reaction is,
$A + B \rightleftharpoons AB$
$k = \dfrac{{\left[ {AB} \right]}}{{\left[ A \right]\left[ B \right]}}$
If $2A + 2B \rightleftharpoons 2AB$
$K = 2AB$. Thus the equilibrium concentration of AB will become twice as its original value.

Note:
We have to know that to discover the equilibrium amounts of every species from the underlying amounts we should know:
The fair condition for the response
The balance articulation for the response
The incentive for the balance consistent
The underlying amounts of every species, either as molarities, or incomplete pressing factors
The response will continue to build up equilibrium.