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In the given reaction,
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Structure of X can be:

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Last updated date: 13th Jun 2024
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Hint: The above reaction is the additional reaction. The hydrogen chloride adds up to a molecule of alkene according to Markovnikov addition and carbocation rearrangement occurs if necessary to form a more stable carbocation.

Complete step by step solution:
It is clear that the reacting molecule is an alkene from the given options. The addition of \[{\text{HCl}}\] in alkene occurs from Markovnikov addition; it says that the nucleophile that is the chloride will attached to that carbon which is more highly substituted or which have lesser number of hydrogen let us write the product in each of the above reaction:
In option A a 5 member ring is given. First of all the carbocation will form at carbon next to the ring and then ring expansion occurs to form the 6 membered ring and hence chloride will react to form the given product.
In Case of option B addition to alkene will occur and the chloride will go to that carbon which is more highly substituted that is the carbon that belongs to the cyclic ring in this the product formed will be the same.
In the same way the Markovnikov addition will occur in option C and the same product will form. Chloride will go to carbon attached with the methyl group because it is highly substituted.
In the option D carbocation rearrangement will occur after addition of hydrogen because tertiary carbocation is more stable than the secondary carbocation. Hence the same product will form.

So in all of them the major product will be:
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Note: First of all alkene attacks the hydrogen and hence a carbocation is formed, the carbocation is formed on the more substituted carbon and then chloride attaches with the carbocation. The electrophile which is generated, that is, the hydrogen ion attaches at the beginning, so it is known as the electrophilic addition reaction.