Courses
Courses for Kids
Free study material
Offline Centres
More
Store

# In the following circuit if ${{V}_{A}}-{{V}_{B}}=4V$ , then the value of resistance X in ohms will be:-a)5b)10c)15d)20

Last updated date: 12th Aug 2024
Total views: 420k
Views today: 4.20k
Verified
420k+ views
Hint: In the above question the potential difference between two points that is A and B is given to us as 60V. In the above question all the components are connected in series. Hence we will use ohm's law to determine the current in the above circuit and then again use it to determine the resistance X in the above circuit.

Formula used:
$V=IR$

Let us say there is a resistance(R) connected to a battery such that the potential difference between the two terminals is (V). Therefore the current in the circuit (I) can be found out by using the relation given to us by ohm's law i.e. $V=IR$.
\begin{align} & {{V}_{AB}}={{V}_{(10\Omega )}}+{{V}_{(5V)}} \\ & \Rightarrow 4V=IR+5V \\ & \Rightarrow -1V=I10\Omega \\ & \Rightarrow I=-\dfrac{1}{10}A \\ \end{align}
\begin{align} & {{V}_{AB}}={{V}_{(X\Omega )}}+{{V}_{(2V)}} \\ & \Rightarrow 4V=\dfrac{1}{10}X+2V \\ & \Rightarrow 2V=\dfrac{1}{10}X \\ & \Rightarrow X=20\Omega \\ \end{align}