Answer

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**Hint**Analyse the diagram given in the question, and derive the equation of the motion of the block from that. Use the potential energy and the kinetic energy in it. The simplification of the above equation provides the value of the velocity of the block.

**Useful formula**

(1) The formula of the potential energy is given by

$P = mgh$

Where $P$ is the potential energy, $m$ is the mass of the block, $g$ is the acceleration due to gravity and $h$ is the height.

(2) The formula of the kinetic energy is given by

$K = \dfrac{1}{2}m{v^2}$

$K$ is the kinetic energy, $v$ is the velocity of motion.

**Complete step by step solution**

It is given that the

$AC,\,DG,\,$ and $GF$ are fixed inclined planes

$BC = EF = x$

$AB = DE = y$

The speed at which the $AC$ reaches $C$ is ${v_c}$ .

The speed at which the block slides down $AC$ and reaches $C$ is ${v_c}$

The coefficient of the kinetic friction is considered as $\mu $

It is known that the potential energy of the block is converted into the kinetic energy while moving.

$P - K = {f_2}{s_1} + {f_2}{s_2}$

Substituting the formula in it,

$mgy - \dfrac{1}{2}mv_F^2 = \mu mg\cos \beta {S_1} - \mu mg\cos \alpha {S_2}$

By simplifying the above equation, we get

**${v_F} = \sqrt {2g\left( {y - \mu x} \right)} $**

**Note**The friction affects the motion of the body when it rolls or slides down the surface. This is because the surface with the diffraction is rough and this reduces the velocity . This sliding motion is due to the acceleration due to gravity and not due to the external force applied on it.

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