Question

In the extraction of iron from haematite, the charge used is haematite, coke and limestone in the following weight ratio.
A)$1:1:1$
B)$8:4:1$
C)$8:1:4$
D)$1:4:8$

Answer 1

Hint: We know that, within the smelting step, the haematite ore is mixed with coke and limestone and this mixture is named a charge.

Complete step by step answer:Now we discuss how iron is obtained from their ore.
Extraction of iron from its ore is the third and thus the penultimate process within the Metallurgy. The extraction of metals and its isolation occurs over a few of major steps,
- Concentration of Ore
- Extraction of metal from concentrated Ore
- Purification of the metal
It’s an extended process which begins with concentration through calcination roasting. Concentration removes the water and other volatile impurities like sulphur and carbonates. Limestone and Coke is mixed with concentration ore and fed into the furnace from the top. It’s within the furnace that extraction of iron occurs. The extraction of iron from its ore could also be an extended and subdued process that helps in separating the useful components from the waste materials like slag.
In the smelting step, the haematite ore is mixed with coke and limestone approximately within the ratio of $8:4:1$ . This mixture is named a charge. It’s fed into the furnace from the highest and a blast of temperature as high as is given.

Therefore, the option B is correct.

Note:In nitromethane, Electron withdrawing groups are present and electron withdrawing is a Nitro group. During this molecule \[N{O_2}\] has partial charge since it attracts the charge density towards its side. Methyl group has partial charge since it suffers from partial loss of charge density. In the case of electron donating groups it is sort of different. Alkyl groups, alkoxy groups belong to the present category. Within the case of toluene (methyl is attached to benzene) the methyl present is electron donating. It donates the electron density to benzene formula.