Answer
Verified
420.9k+ views
Hint: The kinetic energy in a simple harmonic motion can be found by taking the half of the product of the mass and square of the velocity. Using this find out the variation in potential energy and kinetic energy with a displacement. This will help you in answering this question.
Complete answer:
The kinetic energy in a simple harmonic motion can be found by taking the half of the product of the mass and square of the velocity. That is we can write that,
$KE=\dfrac{1}{2}m{{u}^{2}}$
Where $u$ be the velocity. The velocity of the simple pendulum in a SHM can be shown as,
$u=\sqrt{\left( {{A}^{2}}-{{x}^{2}} \right){{\omega }^{2}}}$
Substituting this in the equation of kinetic energy will give,
\[KE=\dfrac{1}{2}m\left( {{A}^{2}}-{{x}^{2}} \right){{\omega }^{2}}\]
As we all know the spring constant can be found as,
\[K=m{{\omega }^{2}}\]
Substituting this value in the equation will give,
\[KE=\dfrac{1}{2}K\left( {{A}^{2}}-{{x}^{2}} \right)\]
For a simple pendulum, the variation in kinetic energy and potential energy with displacement \[d\] will be,
\[\begin{align}
& KE=\dfrac{1}{2}m{{\omega }^{2}}\left( {{A}^{2}}-{{d}^{2}} \right) \\
& PE=\dfrac{1}{2}m{{\omega }^{2}}{{d}^{2}} \\
\end{align}\]
If the displacement is zero, then,
\[\begin{align}
& KE=\dfrac{1}{2}m{{\omega }^{2}}{{A}^{2}} \\
& PE=0 \\
\end{align}\]
If the displacement be,
\[d=\pm A\]
Then we can write that,
\[\begin{align}
& PE=\dfrac{1}{2}m{{\omega }^{2}}{{A}^{2}} \\
& KE=0 \\
\end{align}\]
Using these relations, we can plot the graph. That is the graph will look like this,
Therefore the correct answer has been obtained as option B.
Note:
The potential energy of a system is defined as the energy acquired by the system because of its orientation and position in the space. The kinetic energy of a system is defined as the energy possessed by a body because of the motion of the system. Both of them are having the same units of energy.
Complete answer:
The kinetic energy in a simple harmonic motion can be found by taking the half of the product of the mass and square of the velocity. That is we can write that,
$KE=\dfrac{1}{2}m{{u}^{2}}$
Where $u$ be the velocity. The velocity of the simple pendulum in a SHM can be shown as,
$u=\sqrt{\left( {{A}^{2}}-{{x}^{2}} \right){{\omega }^{2}}}$
Substituting this in the equation of kinetic energy will give,
\[KE=\dfrac{1}{2}m\left( {{A}^{2}}-{{x}^{2}} \right){{\omega }^{2}}\]
As we all know the spring constant can be found as,
\[K=m{{\omega }^{2}}\]
Substituting this value in the equation will give,
\[KE=\dfrac{1}{2}K\left( {{A}^{2}}-{{x}^{2}} \right)\]
For a simple pendulum, the variation in kinetic energy and potential energy with displacement \[d\] will be,
\[\begin{align}
& KE=\dfrac{1}{2}m{{\omega }^{2}}\left( {{A}^{2}}-{{d}^{2}} \right) \\
& PE=\dfrac{1}{2}m{{\omega }^{2}}{{d}^{2}} \\
\end{align}\]
If the displacement is zero, then,
\[\begin{align}
& KE=\dfrac{1}{2}m{{\omega }^{2}}{{A}^{2}} \\
& PE=0 \\
\end{align}\]
If the displacement be,
\[d=\pm A\]
Then we can write that,
\[\begin{align}
& PE=\dfrac{1}{2}m{{\omega }^{2}}{{A}^{2}} \\
& KE=0 \\
\end{align}\]
Using these relations, we can plot the graph. That is the graph will look like this,
Therefore the correct answer has been obtained as option B.
Note:
The potential energy of a system is defined as the energy acquired by the system because of its orientation and position in the space. The kinetic energy of a system is defined as the energy possessed by a body because of the motion of the system. Both of them are having the same units of energy.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
Mark and label the given geoinformation on the outline class 11 social science CBSE
When people say No pun intended what does that mea class 8 english CBSE
Name the states which share their boundary with Indias class 9 social science CBSE
Give an account of the Northern Plains of India class 9 social science CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Trending doubts
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
Which are the Top 10 Largest Countries of the World?
Difference Between Plant Cell and Animal Cell
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Give 10 examples for herbs , shrubs , climbers , creepers
Change the following sentences into negative and interrogative class 10 english CBSE
Write a letter to the principal requesting him to grant class 10 english CBSE