Answer
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Hint: They are the conditions that occur when a plant cell is placed in an isotonic solution. These cells are those whose protoplast has no turgor pressure. In these cells, the plasma membrane isn't pressed tightly against the cell wall.
Complete answer:
In plasmolysis, a plant cell becomes flaccid. Plasmolysis is the shrinking of the protoplasm as a result of water loss from osmosis when a cell comes in contact with a hypertonic solution. When plant cells are placed in a hypertonic solution, it will begin losing water through the method of exosmosis as there's a lesser concentration of solvent molecules than the fluid within the cell therefore the solvent molecules are compelled outside the cell from the region of upper concentration to the lower concentration. The cell turns flaccid. On ahead loss of water, the protoplasm shrinks and moves far away from the cell wall and the cell obtains plasmolyzed. Some real-life samples of Plasmolysis are - shrinkage of vegetables in hypertonic conditions and blood corpuscle shrinks once they are placed within the hypertonic conditions.
Additional Information:
The complete process of Plasmolysis occurs in three steps, which are-
Step1: It's the starting stage of plasmolysis, throughout which water begins flowing out of the cell; initially, the cell shrinks in volume and the cell wall becomes detectable.
Step2: it's the subsequent stage of the plasmolysis, throughout which the cell wall has reached its limit of contraction and cytoplasm, is detached from the cell wall attaining the spherical shape.
Step3: it's the third and the end of the plasmolysis, during which the cytoplasm is going to be completely free from the cell wall and remains within the center of the cell.
So, the correct answer is ‘Becomes flaccid’.
Note: When the plasmolyzed cell is placed during a hypotonic solution, (the solution during which solute concentration is a smaller amount than the cell sap), the water travels into the cell, because of the greater concentration of water outside the cell. Then the cell swells and becomes turgid. This is often referred to as deplasmolysis.
Complete answer:
In plasmolysis, a plant cell becomes flaccid. Plasmolysis is the shrinking of the protoplasm as a result of water loss from osmosis when a cell comes in contact with a hypertonic solution. When plant cells are placed in a hypertonic solution, it will begin losing water through the method of exosmosis as there's a lesser concentration of solvent molecules than the fluid within the cell therefore the solvent molecules are compelled outside the cell from the region of upper concentration to the lower concentration. The cell turns flaccid. On ahead loss of water, the protoplasm shrinks and moves far away from the cell wall and the cell obtains plasmolyzed. Some real-life samples of Plasmolysis are - shrinkage of vegetables in hypertonic conditions and blood corpuscle shrinks once they are placed within the hypertonic conditions.
Additional Information:
The complete process of Plasmolysis occurs in three steps, which are-
Step1: It's the starting stage of plasmolysis, throughout which water begins flowing out of the cell; initially, the cell shrinks in volume and the cell wall becomes detectable.
Step2: it's the subsequent stage of the plasmolysis, throughout which the cell wall has reached its limit of contraction and cytoplasm, is detached from the cell wall attaining the spherical shape.
Step3: it's the third and the end of the plasmolysis, during which the cytoplasm is going to be completely free from the cell wall and remains within the center of the cell.
So, the correct answer is ‘Becomes flaccid’.
Note: When the plasmolyzed cell is placed during a hypotonic solution, (the solution during which solute concentration is a smaller amount than the cell sap), the water travels into the cell, because of the greater concentration of water outside the cell. Then the cell swells and becomes turgid. This is often referred to as deplasmolysis.
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