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In period 3 of the periodic table, element B is placed to the left of the element A. based on this information, choose a word from the brackets to complete the following statements:
(a)- The element B would (lower/higher) metallic character than A.
(b)- The element A would probably have (lesser/higher) electron affinity than B.
(c)- The element A would have (greater/smaller) atomic size than B.

Answer Verified Verified
Hint: The metallic character decreases while moving from left to right in a period. The electron affinity increases while moving from left to right in a period. The atomic size decreases while moving from left to right in a period.

Complete answer:
As the question says element B is placed to the left of element A, therefore while moving from left to right in a period B will be the first element and A will be the second.
(a)- The element B would (lower/higher) metallic character than A.
Metallic character is the tendency to lose an electron to form positive ions. Metallic character increases down the group and decreases while moving along the period. Hence,
The element B would higher metallic character than A

(b)- The element A would probably have (lesser/higher) electron affinity than B.
Electron affinity is the tendency of an element to accept an extra electron and acquire a negative charge.
As we move down the group the electron affinity decreases and as we move along the period the electron affinity increases. Hence,
The element A would probably have a higher electron affinity than B.

(c)- The element A would have (greater/smaller) atomic size than B.
Atomic size or radius is the distance between the center of the nucleus and the outermost shell containing the electron.
Atomic size increases down the group and decreases while moving along the period. Hence,
The element A would have a smaller atomic size than B.

Note: The correct trend of all factors should be kept in mind. Along with atomic size, the metallic size and covalent size also decreases while moving along the period.