Answer
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Hint: We know that iodine is a non-metallic element, called halogen. And ether is a polar organic solvent. In ether an oxygen atom connected to two alkyl or aryl groups.
Step by step solution:
When we take an iodine in ether for charge transfer test Ether form a compound with ether it means ether react with iodine or iodine react with ether. And iodine breaks into ions. Here is the reaction if ether and iodine:
\[R-O-{{R}^{'}}\xrightarrow{{{I}_{2}}}{{R}^{'}}I+RI+{{H}_{2}}O\]
Here, \[R\] and \[{{R}^{'}}\] are alkyl or aryl groups.
And we know that pure iodine has a violet color. When iodine is dissolved in different solutions it gives different colors.
When iodine is in non-polar solvents like benzene and carbon tetrachloride it will give a purple color solution.
And when iodine is in polar solvents like water and ethanol, it gives a brown color solution.
And we know that ether is also polar solvent. Ethers are more polar than alkenes but less polar than alcohols, esters, or amides. So, iodine will give brown solution in ether. Iodine reacts with ether and charge transfer phenomenon takes place.
So, from the above points it is clear that the correct option is “C”.
Note: Here, in this problem we should remember that in which color iodine gives which color. In non-polar solvents iodine is simply solvated and in polar solvents iodine is chemically combined with solvent.
Step by step solution:
When we take an iodine in ether for charge transfer test Ether form a compound with ether it means ether react with iodine or iodine react with ether. And iodine breaks into ions. Here is the reaction if ether and iodine:
\[R-O-{{R}^{'}}\xrightarrow{{{I}_{2}}}{{R}^{'}}I+RI+{{H}_{2}}O\]
Here, \[R\] and \[{{R}^{'}}\] are alkyl or aryl groups.
And we know that pure iodine has a violet color. When iodine is dissolved in different solutions it gives different colors.
When iodine is in non-polar solvents like benzene and carbon tetrachloride it will give a purple color solution.
And when iodine is in polar solvents like water and ethanol, it gives a brown color solution.
And we know that ether is also polar solvent. Ethers are more polar than alkenes but less polar than alcohols, esters, or amides. So, iodine will give brown solution in ether. Iodine reacts with ether and charge transfer phenomenon takes place.
So, from the above points it is clear that the correct option is “C”.
Note: Here, in this problem we should remember that in which color iodine gives which color. In non-polar solvents iodine is simply solvated and in polar solvents iodine is chemically combined with solvent.
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