In a Kundt’s tube experiment, the heaps of lycopodium powder are collected at 20cm separations. What will be the frequency of the tuning fork used?
\[\begin{align}
& A.\text{ 660Hz} \\
& \text{B}\text{. 825Hz} \\
& \text{C}\text{. 775Hz} \\
& \text{D}\text{. 915Hz} \\
\end{align}\]
Answer
603.3k+ views
Hint: The Kundt’s tube experiment is the acoustic experiment which describes the longitudinal wave pattern in the sound waves. The separation of piles formed by the given sample is a direct indicator of the characteristics of the sound wave used. The speed of sound in air is 340\[m{{s}^{-1}}\].
Formula Used:
The basic formula used in a Kundt’s experiment is –
\[c=\lambda \nu \]
Where, c is the speed of sound in vacuum or air
\[\lambda \] is the wavelength of the sound
\[\nu \] is the frequency of the sound
Complete answer:
The Kundt’s tube experiment consists of a transparent horizontal tube with a small amount of the given sample, here it is the lycopodium. The one end of the tube has a single signal generator which can produce a sound wave of single frequency \[\nu \]. The other end of the tube is attached with a movable piston which can oscillate along with the incoming sound wave and thus contributes to the length of the tube. The piston is set up such that the sound produced by the generator doesn’t disturb its equilibrium position at lower amplitudes. This means that the length of the tube along with the piston is a multiple of the wavelength of the generated sound.
The given figures give the amplitude variation at two instincts.
It is clear that the piston will be at equilibrium if \[L=n\lambda \].
Also, we know from the experiment that the powder used has a tendency to pile at distance half of the wavelengths.
Now using this idea and given data, we can find the frequency of the sound used.
\[\begin{align}
& \text{Given}, \\
& \text{ }\delta =20cm \\
& \text{Also}, \\
& \text{ }\dfrac{\lambda }{2}=\delta \\
& \Rightarrow \dfrac{\lambda }{2}=20cm \\
& \Rightarrow \lambda =40cm\text{ --------(1)} \\
\end{align}\]
Now, using the basic formula relating speed, wavelength and frequency we can find the frequency of the sound.
\[\begin{align}
& c=\lambda \nu \text{ -------(2)} \\
& \text{From (1),} \\
& \lambda =40cm=0.4m \\
& \text{Also,} \\
& c=340m{{s}^{-1}} \\
& \Rightarrow \text{From (2),} \\
& \text{ }\nu =\dfrac{c}{\lambda } \\
& \Rightarrow \nu =\dfrac{340}{0.4} \\
& \Rightarrow \nu =850Hz \\
\end{align}\]
The frequency with which the experiment was conducted is 850Hz.
Option B is the suitable answer.
Note:
In an experiment, the unknown we usually find is the wavelength of the generated sound wave. We find it similarly by measuring the distance between the piles of the lycopodium powder and applying the basic formula relating wavelength, frequency and speed of sound in the medium.
The experiment is also a proof for the longitudinal nature of the sound waves.
Formula Used:
The basic formula used in a Kundt’s experiment is –
\[c=\lambda \nu \]
Where, c is the speed of sound in vacuum or air
\[\lambda \] is the wavelength of the sound
\[\nu \] is the frequency of the sound
Complete answer:
The Kundt’s tube experiment consists of a transparent horizontal tube with a small amount of the given sample, here it is the lycopodium. The one end of the tube has a single signal generator which can produce a sound wave of single frequency \[\nu \]. The other end of the tube is attached with a movable piston which can oscillate along with the incoming sound wave and thus contributes to the length of the tube. The piston is set up such that the sound produced by the generator doesn’t disturb its equilibrium position at lower amplitudes. This means that the length of the tube along with the piston is a multiple of the wavelength of the generated sound.
The given figures give the amplitude variation at two instincts.
It is clear that the piston will be at equilibrium if \[L=n\lambda \].
Also, we know from the experiment that the powder used has a tendency to pile at distance half of the wavelengths.
Now using this idea and given data, we can find the frequency of the sound used.
\[\begin{align}
& \text{Given}, \\
& \text{ }\delta =20cm \\
& \text{Also}, \\
& \text{ }\dfrac{\lambda }{2}=\delta \\
& \Rightarrow \dfrac{\lambda }{2}=20cm \\
& \Rightarrow \lambda =40cm\text{ --------(1)} \\
\end{align}\]
Now, using the basic formula relating speed, wavelength and frequency we can find the frequency of the sound.
\[\begin{align}
& c=\lambda \nu \text{ -------(2)} \\
& \text{From (1),} \\
& \lambda =40cm=0.4m \\
& \text{Also,} \\
& c=340m{{s}^{-1}} \\
& \Rightarrow \text{From (2),} \\
& \text{ }\nu =\dfrac{c}{\lambda } \\
& \Rightarrow \nu =\dfrac{340}{0.4} \\
& \Rightarrow \nu =850Hz \\
\end{align}\]
The frequency with which the experiment was conducted is 850Hz.
Option B is the suitable answer.
Note:
In an experiment, the unknown we usually find is the wavelength of the generated sound wave. We find it similarly by measuring the distance between the piles of the lycopodium powder and applying the basic formula relating wavelength, frequency and speed of sound in the medium.
The experiment is also a proof for the longitudinal nature of the sound waves.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

