Answer
414.6k+ views
Hint:We all know that the empirical formula of a compound is the simplest whole number ratio of each type of atom in a compound. An empirical formula is calculated from information about the mass of each element in a compound or from the percentage composition.
Complete step by step answer:
The mass ratio of carbon, hydrogen and nitrogen are present in $9:1:3.5$
The molecular weight of the substance can be calculated as,
The atomic weight of carbon is $12$.
The atomic weight of hydrogen is $1$.
The molecular weight of nitrogen is $14$.
Molar ratio of $C:H:N = \dfrac{9}{{12}}:\dfrac{1}{1}:\dfrac{{3.5}}{{14}} = 0.75:1:0.25$
The smaller ratio is$0.25$.
The integer ratio is $ = \dfrac{{0.75}}{{0.25}}:\dfrac{1}{{0.25}}:\dfrac{{0.25}}{{0.25}} = 3:4:1$
Thus the empirical formula of the compound is ${C_3}{H_4}N$
The empirical weight of the compound is $54g$.
The molecular formula is the expression of the number of atoms of each element in one molecule of a compound if the molar mass value is known the molecular formula is calculated by the empirical formula.
${\text{n}} = \dfrac{{{\text{Molar mass}}}}{{{\text{Mass of the empirical formula}}}}$
Substituting the values we get,
$ \Rightarrow $${\text{n}} = \dfrac{{108}}{{54}} = 2$
The molecular formula of the compound is ${C_6}{H_8}{N_2}$.
Therefore option C is correct.
Note: Now discuss about the steps for determining the empirical formula of a compound as follows:
The mass of each element present in grams has to be calculated.
The number of moles of each atom present has to be found.
The number of moles of each element has to be divided by the smallest number of moles.
The numbers of moles have to be converted to whole numbers. The set of whole numbers are the subscripts in the empirical formula.
Complete step by step answer:
The mass ratio of carbon, hydrogen and nitrogen are present in $9:1:3.5$
The molecular weight of the substance can be calculated as,
The atomic weight of carbon is $12$.
The atomic weight of hydrogen is $1$.
The molecular weight of nitrogen is $14$.
Molar ratio of $C:H:N = \dfrac{9}{{12}}:\dfrac{1}{1}:\dfrac{{3.5}}{{14}} = 0.75:1:0.25$
The smaller ratio is$0.25$.
The integer ratio is $ = \dfrac{{0.75}}{{0.25}}:\dfrac{1}{{0.25}}:\dfrac{{0.25}}{{0.25}} = 3:4:1$
Thus the empirical formula of the compound is ${C_3}{H_4}N$
The empirical weight of the compound is $54g$.
The molecular formula is the expression of the number of atoms of each element in one molecule of a compound if the molar mass value is known the molecular formula is calculated by the empirical formula.
${\text{n}} = \dfrac{{{\text{Molar mass}}}}{{{\text{Mass of the empirical formula}}}}$
Substituting the values we get,
$ \Rightarrow $${\text{n}} = \dfrac{{108}}{{54}} = 2$
The molecular formula of the compound is ${C_6}{H_8}{N_2}$.
Therefore option C is correct.
Note: Now discuss about the steps for determining the empirical formula of a compound as follows:
The mass of each element present in grams has to be calculated.
The number of moles of each atom present has to be found.
The number of moles of each element has to be divided by the smallest number of moles.
The numbers of moles have to be converted to whole numbers. The set of whole numbers are the subscripts in the empirical formula.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Why Are Noble Gases NonReactive class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let X and Y be the sets of all positive divisors of class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x and y be 2 real numbers which satisfy the equations class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x 4log 2sqrt 9k 1 + 7 and y dfrac132log 2sqrt5 class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x22ax+b20 and x22bx+a20 be two equations Then the class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Which are the Top 10 Largest Countries of the World?
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Write a letter to the principal requesting him to grant class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Give 10 examples for herbs , shrubs , climbers , creepers
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Fill in the blanks A 1 lakh ten thousand B 1 million class 9 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Change the following sentences into negative and interrogative class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference Between Plant Cell and Animal Cell
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)