If $z$ is a complex number such that $\left| z \right| \geqslant 2$ then the minimum value of $\left| {z + \frac{1}{2}} \right|$ is
A. Is strictly greater than $\frac{5}{2}$
B. Is strictly greater than $\frac{3}{2}$ but less than $\frac{5}{2}$
C. Is equal to $\frac{5}{2}$
D. Lies in the interval $(1,2)$
Answer
620.4k+ views
Hint: For solving this particular question we have to analysis that $\left| z \right|\geqslant 2$ is the region on or outside the circle whose centre is $(0,0)$and the radius is two. And minimum $\left| {z + \frac{1}{z}} \right|$ is equal to distance between $\left( { - \frac{1}{2},0} \right)$ to $(0,0)$ .
Complete solution step by step:
It is given that $z$ is a complex number such that $\left| z \right| \geqslant 2$ ,
$\left| z \right| \geqslant 2$ is the region on or outside the circle whose centre is $(0,0)$ and the radius is two.
Minimum $\left| {z + \frac{1}{z}} \right|$ is distance of $z$ which lies on the circle $\left| z \right|
= 2$ from $\left( { - \frac{1}{2},0} \right)$ ,
Thus minimum $\left| {z + \frac{1}{z}} \right|$ is equal to distance between $\left( { - \frac{1}{2},0} \right)$ to $(0,0)$ .
$\begin{gathered}
= \sqrt {{{\left( { - \frac{1}{2} + 2} \right)}^2} + {{(0 - 0)}^2}} \\
= \sqrt {{{\left( { - \frac{1}{2} + 2} \right)}^2}} \\
\end{gathered} $
Now apply radial rule that is , $\sqrt[n]{{{a^n}}} = a$ where $a \geqslant 0$ ,
Therefore , we will get ,
$\begin{gathered}
= - \frac{1}{2} + 2 \\
= \frac{{ - 1 + 4}}{2} \\
= \frac{3}{2} \\
\end{gathered} $
Hence , option B is the correct option.
Additional information: As we know that $z = x + yi$ , which is the representation of the complex number. And $z = x - yi$ , is the conjugate of the complex number.
Now multiplication of the complex number with the conjugate of the complex number we get magnitude which represents the distance of the complex number from the origin. we know that ${\left| {{z_1}} \right|^2} = {z_1}\overline {{z_1}} $ , multiplication of the complex number with the conjugate of the complex number we get magnitude which represents the distance of the complex number from the origin.
Note: If $z = x + yi$ be any complex number then modulus of $z$ is represented as $\left| z \right|$ and is equal to $\sqrt {{x^2} + {y^2}} $ . Here $\left| z \right| \geqslant 2$ is the region on or outside the circle whose centre is $(0,0)$and the radius is two.
Complete solution step by step:
It is given that $z$ is a complex number such that $\left| z \right| \geqslant 2$ ,
$\left| z \right| \geqslant 2$ is the region on or outside the circle whose centre is $(0,0)$ and the radius is two.
Minimum $\left| {z + \frac{1}{z}} \right|$ is distance of $z$ which lies on the circle $\left| z \right|
= 2$ from $\left( { - \frac{1}{2},0} \right)$ ,
Thus minimum $\left| {z + \frac{1}{z}} \right|$ is equal to distance between $\left( { - \frac{1}{2},0} \right)$ to $(0,0)$ .
$\begin{gathered}
= \sqrt {{{\left( { - \frac{1}{2} + 2} \right)}^2} + {{(0 - 0)}^2}} \\
= \sqrt {{{\left( { - \frac{1}{2} + 2} \right)}^2}} \\
\end{gathered} $
Now apply radial rule that is , $\sqrt[n]{{{a^n}}} = a$ where $a \geqslant 0$ ,
Therefore , we will get ,
$\begin{gathered}
= - \frac{1}{2} + 2 \\
= \frac{{ - 1 + 4}}{2} \\
= \frac{3}{2} \\
\end{gathered} $
Hence , option B is the correct option.
Additional information: As we know that $z = x + yi$ , which is the representation of the complex number. And $z = x - yi$ , is the conjugate of the complex number.
Now multiplication of the complex number with the conjugate of the complex number we get magnitude which represents the distance of the complex number from the origin. we know that ${\left| {{z_1}} \right|^2} = {z_1}\overline {{z_1}} $ , multiplication of the complex number with the conjugate of the complex number we get magnitude which represents the distance of the complex number from the origin.
Note: If $z = x + yi$ be any complex number then modulus of $z$ is represented as $\left| z \right|$ and is equal to $\sqrt {{x^2} + {y^2}} $ . Here $\left| z \right| \geqslant 2$ is the region on or outside the circle whose centre is $(0,0)$and the radius is two.
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

