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Hint: Here, we will be finding the value of angle $\theta $ from the given equation and then we will be using the values like $\tan {45^0} = 1$ and \[\sin {45^0} = \dfrac{1}{{\sqrt 2 }}\] given in the trigonometric table in order to obtain the value of the given expression.

Complete step-by-step answer:

Given, $\sin \theta = \cos \theta $ where $\theta $ is an acute angle

As we know that $\tan \theta = \dfrac{{\sin \theta }}{{\cos \theta }}$

The given equation can be rearranged as $

\Rightarrow \dfrac{{\sin \theta }}{{\cos \theta }} = 1 \\

\Rightarrow \tan \theta = 1{\text{ }} \to {\text{(1)}} \\

$

Also we know that tangent of 45 degrees is equal to 1 i.e., $\tan {45^0} = 1{\text{ }} \to {\text{(2)}}$

By comparing equations (1) and (2), we will get the value for $\theta $

$ \Rightarrow \theta = {45^0}$

Here, we have considered only $\theta = {45^0}$ because it is given that $\theta $ is an acute angle (angle which is less than 90 degrees).

Let us suppose the value of expression whose value we need to find is x

So, $x = 2{\left( {\tan \theta } \right)^2} + {\left( {\sin \theta } \right)^2} - 1$

Now, let us substitute the value of $\theta = {45^0}$ in the above expression in order to find the value of x.

\[

\Rightarrow x = 2{\left( {\tan \theta } \right)^2} + {\left( {\sin \theta } \right)^2} - 1 \\

\Rightarrow x = 2{\left( {\tan {{45}^0}} \right)^2} + {\left( {\sin {{45}^0}} \right)^2} - 1{\text{ }} \to {\text{(3)}} \\

\]

According to trigonometric table, we can write

\[\tan {45^0} = 1\] and \[\sin {45^0} = \dfrac{1}{{\sqrt 2 }}\]

Putting these values in equation (3), we get

\[ \Rightarrow x = 2{\left( 1 \right)^2} + {\left( {\dfrac{1}{{\sqrt 2 }}} \right)^2} - 1 = 2 + \dfrac{1}{2} - 1 = 1 + \dfrac{1}{2} = \dfrac{{2 + 1}}{2} = \dfrac{3}{2}\]

Therefore, the value of the expression is given by \[2{\left( {\tan \theta } \right)^2} + {\left( {\sin \theta } \right)^2} - 1 = \dfrac{3}{2}\].

Note: In this problem, the important step lies in the determination of the angle $\theta $ because $\tan \theta = 1$ gives various values of $\theta $ as $\theta = {45^0},{225^0},{405^0}$, etc but in the problem it is given that $\theta $ is an acute angle so we will consider only that value of $\theta $ which measures less than ${90^0}$. That’s why the only possible result of $\tan \theta = 1$ is $\theta = {45^0}$.

Complete step-by-step answer:

Given, $\sin \theta = \cos \theta $ where $\theta $ is an acute angle

As we know that $\tan \theta = \dfrac{{\sin \theta }}{{\cos \theta }}$

The given equation can be rearranged as $

\Rightarrow \dfrac{{\sin \theta }}{{\cos \theta }} = 1 \\

\Rightarrow \tan \theta = 1{\text{ }} \to {\text{(1)}} \\

$

Also we know that tangent of 45 degrees is equal to 1 i.e., $\tan {45^0} = 1{\text{ }} \to {\text{(2)}}$

By comparing equations (1) and (2), we will get the value for $\theta $

$ \Rightarrow \theta = {45^0}$

Here, we have considered only $\theta = {45^0}$ because it is given that $\theta $ is an acute angle (angle which is less than 90 degrees).

Let us suppose the value of expression whose value we need to find is x

So, $x = 2{\left( {\tan \theta } \right)^2} + {\left( {\sin \theta } \right)^2} - 1$

Now, let us substitute the value of $\theta = {45^0}$ in the above expression in order to find the value of x.

\[

\Rightarrow x = 2{\left( {\tan \theta } \right)^2} + {\left( {\sin \theta } \right)^2} - 1 \\

\Rightarrow x = 2{\left( {\tan {{45}^0}} \right)^2} + {\left( {\sin {{45}^0}} \right)^2} - 1{\text{ }} \to {\text{(3)}} \\

\]

According to trigonometric table, we can write

\[\tan {45^0} = 1\] and \[\sin {45^0} = \dfrac{1}{{\sqrt 2 }}\]

Putting these values in equation (3), we get

\[ \Rightarrow x = 2{\left( 1 \right)^2} + {\left( {\dfrac{1}{{\sqrt 2 }}} \right)^2} - 1 = 2 + \dfrac{1}{2} - 1 = 1 + \dfrac{1}{2} = \dfrac{{2 + 1}}{2} = \dfrac{3}{2}\]

Therefore, the value of the expression is given by \[2{\left( {\tan \theta } \right)^2} + {\left( {\sin \theta } \right)^2} - 1 = \dfrac{3}{2}\].

Note: In this problem, the important step lies in the determination of the angle $\theta $ because $\tan \theta = 1$ gives various values of $\theta $ as $\theta = {45^0},{225^0},{405^0}$, etc but in the problem it is given that $\theta $ is an acute angle so we will consider only that value of $\theta $ which measures less than ${90^0}$. That’s why the only possible result of $\tan \theta = 1$ is $\theta = {45^0}$.

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