
If the solubility of a compound is $ 36{\text{ }}gram{\text{ }}per{\text{ }}liter $ , how many grams of the compound will dissolve in $ 5liters $ ?
Answer
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Hint: In order to answer this question, to know the quantity of the compound will dissolve in $ 5liters $ , we should go through the simplest calculation or we can say that the simplest method. Like, in $ 1liter $ , the solubility of a compound is $ 36grams $ . Then in $ 5liters $ , what is the solubility.
Complete step by step answer:
Given that-
The solubility of a compound is $ 36grams $ in $ 1liter $.
Then, the solubility of the same compound in $ 5liters $ is $ 36 \times 5\,grams = 180grams $.
Hence, $ 180grams $ of the compound will dissolve in $ 5liters $.
Solubility is the measure of the maximum amount of solute that can be dissolved in a given quantity of solvent at a given temperature and pressure. Solubility is usually measured in molarity $ (M) $ or $ moles{\text{ }}per{\text{ }}liter{\text{ }}(mol/L) $. A compound is termed soluble if it dissolves in water.
Note:
From the various observations and experimental results, it has been seen that only polar solutes tend to dissolve in the polar solvent and non-polar solvents dissolve only nonpolar solutes. Hence, the nature of the solvent can be seen as one of the prominent factors affecting solubility.
Complete step by step answer:
Given that-
The solubility of a compound is $ 36grams $ in $ 1liter $.
Then, the solubility of the same compound in $ 5liters $ is $ 36 \times 5\,grams = 180grams $.
Hence, $ 180grams $ of the compound will dissolve in $ 5liters $.
Solubility is the measure of the maximum amount of solute that can be dissolved in a given quantity of solvent at a given temperature and pressure. Solubility is usually measured in molarity $ (M) $ or $ moles{\text{ }}per{\text{ }}liter{\text{ }}(mol/L) $. A compound is termed soluble if it dissolves in water.
Note:
From the various observations and experimental results, it has been seen that only polar solutes tend to dissolve in the polar solvent and non-polar solvents dissolve only nonpolar solutes. Hence, the nature of the solvent can be seen as one of the prominent factors affecting solubility.
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