# If the rate of change of sine of angle $\theta $ is $K$, then the rate of change of its tangent is,

(A) ${{K}^{2}}$

(B) $\dfrac{1}{{{K}^{2}}}$

(C) $K$

(D) $\dfrac{1}{K}$

Last updated date: 22nd Mar 2023

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Answer

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Hint: Rate of change of sine of any angle $\theta $ is equal to cosine of that angle $\theta $. Also, rate of change of tangent of $\theta $ is equal to square of secant of $\theta $. Use, $\cos \theta =\dfrac{1}{\sec \theta }$ and substitute the value of $\cos \theta $, obtained by differentiating $\sin \theta $.

The derivative of a function of a real variable measures the sensitivity to change of the function value with respect to a change in its argument value. Derivatives are a fundamental tool of calculus, for example, the derivative of the position of a moving object with respect to time is the object’s velocity, this measures how quickly the position of the object changes when time advances. This derivative is referred to as the instantaneous rate of change. Whenever we are asked to find the rate of change of any function, we just find the derivative of that function or in other words, simply differentiate the function.

Now, we come to the question. It has been given that the rate of change of $\sin \theta $$=K$. We know that, derivative of $\sin \theta $$=\cos \theta $. Therefore, we get, $\cos \theta =K$………………………………..(i).

Also, we know that derivative of $\tan \theta ={{\sec }^{2}}\theta $. Now,$\sec \theta =\dfrac{1}{\cos \theta }$, therefore, substituting the value of $\cos \theta $ from equation (i), we get rate of change of $\tan \theta =\dfrac{1}{{{\cos }^{2}}\theta }=\dfrac{1}{{{K}^{2}}}$.

Hence, option (b) is the correct answer.

Note: Rate of change are of two types: (i) instantaneous rate of change and (ii) average rate of change. Here, we have applied an instantaneous rate of change because according to the question we have to find the derivative of $\sin \theta $ and $\tan \theta $ with respect to angle $\theta $.

__Complete step-by-step answer:__The derivative of a function of a real variable measures the sensitivity to change of the function value with respect to a change in its argument value. Derivatives are a fundamental tool of calculus, for example, the derivative of the position of a moving object with respect to time is the object’s velocity, this measures how quickly the position of the object changes when time advances. This derivative is referred to as the instantaneous rate of change. Whenever we are asked to find the rate of change of any function, we just find the derivative of that function or in other words, simply differentiate the function.

Now, we come to the question. It has been given that the rate of change of $\sin \theta $$=K$. We know that, derivative of $\sin \theta $$=\cos \theta $. Therefore, we get, $\cos \theta =K$………………………………..(i).

Also, we know that derivative of $\tan \theta ={{\sec }^{2}}\theta $. Now,$\sec \theta =\dfrac{1}{\cos \theta }$, therefore, substituting the value of $\cos \theta $ from equation (i), we get rate of change of $\tan \theta =\dfrac{1}{{{\cos }^{2}}\theta }=\dfrac{1}{{{K}^{2}}}$.

Hence, option (b) is the correct answer.

Note: Rate of change are of two types: (i) instantaneous rate of change and (ii) average rate of change. Here, we have applied an instantaneous rate of change because according to the question we have to find the derivative of $\sin \theta $ and $\tan \theta $ with respect to angle $\theta $.

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