
If the lines \[{a_1}x + {b_1} y + {c_1} = 0\] and \[{a_2}x + {b_2} y + {c_2} = 0\] cut the coordinate axis in concyclic points, then
A ${a_1} {a_2} = {b_1} {b_2} $
B $\dfrac{{{a_1}}} {{{a_2}}} = \dfrac{{{b_1}}} {{{b_2}}} $
C ${a_1} + {a_2} = {b_1} + {b_2} $
D ${a_1} {b_1} = {a_2} {b_2} $
Answer
565.8k+ views
Hint: In this question we have been given equations of two lines which cut the coordinate axis in concyclic points which gives us a very important relation. Let suppose the first line intersect at the points A and B and similarly the second line at the points C and D. AB and CD are chords around the x and the y axis with origin O. Therefore, the relation between the points A, B, C, D, as they are concyclic would be $OA \times OB = OC \times OD$. We would use this relation to solve the equation further and find the relation between ${a_1}, {a_2}, {b_1}, {b_2} $.
Complete step-by-step answer:
We have been provided with two equation \[{a_1}x + {b_1} y + {c_1} = 0\] and \[{a_2}x + {b_2} y + {c_2} = 0\]. So, we will be finding the coordinates of both the equations one by one.
The first equation is \[{a_1}x + {b_1}y + {c_1} = 0\] , so the coordinates of this equation will be $A\left( {\dfrac{{ - {c_1}}}{{{a_1}}},0} \right)$ and $B\left( {0,\dfrac{{ - {c_1}}}{{{b_1}}}} \right)$
Similarly, for the second equation \[{a_2}x + {b_2}y + {c_2} = 0\], the coordinates would be $C\left( {\dfrac{{ - {c_2}}}{{{a_2}}},0} \right)$ and $D\left( {0,\dfrac{{ - {c_2}}}{{{b_2}}}} \right)$
Now these coordinate points AB and CD are chords for the x and y axis respectively around the origin O.
And since these points A, B, C, D, are concyclic the following relation would be true for them $OA \times OB = OC \times OD$.
Now keeping the values of these points in the above relation
The values will be $\left( {\dfrac{{ - {c_1}}}{{{a_1}}}} \right) \times \dfrac{{ - {c_2}}}{{{a_2}}} = \left( {\dfrac{{ - {c_1}}}{{{b_1}}}} \right) \times \dfrac{{ - {c_2}}}{{{b_2}}}$
Now solving this equation using cross multiplication method the final relation comes out to be ${a_1} {a_2} = {b_1} {b_2} $
So, the answer comes out to be ${a_1} {a_2} = {b_1} {b_2} $ which is your option (a).
So, the correct answer is “Option A”.
Note: Whenever we are provided with options in a particular question never just try to put all the possible answers in the equation rather than try to find the hint as in this question we were provided that the coordinates are concyclic so from there we were able to obtain the relation to solve this question.
Complete step-by-step answer:
We have been provided with two equation \[{a_1}x + {b_1} y + {c_1} = 0\] and \[{a_2}x + {b_2} y + {c_2} = 0\]. So, we will be finding the coordinates of both the equations one by one.
The first equation is \[{a_1}x + {b_1}y + {c_1} = 0\] , so the coordinates of this equation will be $A\left( {\dfrac{{ - {c_1}}}{{{a_1}}},0} \right)$ and $B\left( {0,\dfrac{{ - {c_1}}}{{{b_1}}}} \right)$
Similarly, for the second equation \[{a_2}x + {b_2}y + {c_2} = 0\], the coordinates would be $C\left( {\dfrac{{ - {c_2}}}{{{a_2}}},0} \right)$ and $D\left( {0,\dfrac{{ - {c_2}}}{{{b_2}}}} \right)$
Now these coordinate points AB and CD are chords for the x and y axis respectively around the origin O.
And since these points A, B, C, D, are concyclic the following relation would be true for them $OA \times OB = OC \times OD$.
Now keeping the values of these points in the above relation
The values will be $\left( {\dfrac{{ - {c_1}}}{{{a_1}}}} \right) \times \dfrac{{ - {c_2}}}{{{a_2}}} = \left( {\dfrac{{ - {c_1}}}{{{b_1}}}} \right) \times \dfrac{{ - {c_2}}}{{{b_2}}}$
Now solving this equation using cross multiplication method the final relation comes out to be ${a_1} {a_2} = {b_1} {b_2} $
So, the answer comes out to be ${a_1} {a_2} = {b_1} {b_2} $ which is your option (a).
So, the correct answer is “Option A”.
Note: Whenever we are provided with options in a particular question never just try to put all the possible answers in the equation rather than try to find the hint as in this question we were provided that the coordinates are concyclic so from there we were able to obtain the relation to solve this question.
Recently Updated Pages
Master Class 11 Chemistry: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

How many 5 digit telephone numbers can be constructed class 11 maths CBSE

Draw a well labelled diagram of reflex arc and explain class 11 biology CBSE

What is the difference between noise and music Can class 11 physics CBSE

Trending doubts
1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

In what year Guru Nanak Dev ji was born A15 April 1469 class 11 social science CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Write the differences between monocot plants and dicot class 11 biology CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 ton equals to A 100 kg B 1000 kg C 10 kg D 10000 class 11 physics CBSE

