Questions & Answers

Question

Answers

(A). $\dfrac{{b - c}}{2}$

(B). $\dfrac{{c - b}}{2}$

(C). $\dfrac{{b + c}}{2}$

(D). $b + \dfrac{c}{2}$

(E). $c + \dfrac{b}{2}$

Answer
Verified

In the question, it says a team won c games in two seasons. That is the current season and previous season. Also, the same team won b fewer games. It means, if it would have won 10 games in the previous season then this season it won only 10-b games. (That’s how algebraic questions work).

Here, we need to find the total matches won in last year’s season.

To calculate this, we’ll first let the total number of matches won last season is y and matches won this season is x.

Now according to the given condition, c is the sum of total matches won in both seasons so,

$x + y = c - - - - - (1)$

On using the condition, team won b fewer matches then previous season, we get,

$x = y - b - - - - - - (2)$

In order to solve this question, we’ll simply solve equation (1) and (2).

On putting the value of x in equation (1) from equation (2).

$

y - b + y = c \\

\Rightarrow 2y = c + b \\

\Rightarrow y = \dfrac{{c + b}}{2} \\

$

We had to find the number of matches won last year’s season and we assumed it as y. Now we have got its value as $\dfrac{{c + b}}{2}$.