
If $ \sin x = \cos x $ and x is acute state the value of x in degrees
Answer
581.7k+ views
Hint: We have been given a trigonometric equation, by making certain changes to it and using various trigonometric identities, we can easily obtain the required value of angle x. This angle x is given to be acute, which means its value is less than 90°.
Trigonometric identities to be used:
$
{\sin ^2}x + {\cos ^2}x = 1 \\
\sin 2x = 2\sin x\cos x \;
$
Complete step-by-step answer:
We have been given an equation:
$ \sin x = \cos x $ and we need to find the value of angle x in degrees.
This equation can be written as:
$ \sin x - \cos x = 0 $
Squaring both the sides, we get:
$
{\left( {\sin x - \cos x} \right)^2} = 0 \\
{\sin ^2}x + {\cos ^2}x - 2\sin x\cos x = 0 \\
1 - 2\sin x\cos x = 0\left( {\because {{\sin }^2}x + {{\cos }^2}x = 1} \right) \;
1 = 2\sin x\cos x \;
$
The value of double sine angle is given as:
$ \sin 2x = 2\sin x\cos x $
Substituting this value, we get:
$ \sin 2x = 1 $
The value of sin 90° is 1, so the above equation can be written as:
$
\sin 2x = \sin {90^\circ } \\
\Rightarrow 2x = {90^\circ } \\
\therefore x = {45^\circ } \;\
$
It is given that the angle is acute i.e. less than 90° which is also true for the angle obtained.
Therefore, if $ \sin x = \cos x $ and x is acute then the value of x is 45 degrees
So, the correct answer is “ 45° ”.
Note: We can also find the value of angle x by the following method, using the basic formula for tanx i.e. \[\dfrac{{\sin x}}{{\cos x}} = \tan x\]
Given equation: $ \sin x = \cos x $
Dividing both the sides by $ \cos x $ , we get:
\[
\dfrac{{\sin x}}{{\cos x}} = \dfrac{{\cos x}}{{\cos x}} \\
\tan x = 1 \\
\left( {\because \dfrac{{\sin x}}{{\cos x}} = \tan x} \right) \\
\]
The value of tan is 1 when the angle is equal to 45°, x can be calculated mathematically as:
$
\tan x = 1 \\
\Rightarrow x = {\tan ^{ - 1}}(1) \\
\therefore x = {45^\circ }\left( {\because \tan {{45}^\circ } = 1} \right) \;
$
Thus, we get the value of x as 45° by following every method.
The angles less than 90° are called acute angles and greater than that are called obtuse.
Trigonometric identities to be used:
$
{\sin ^2}x + {\cos ^2}x = 1 \\
\sin 2x = 2\sin x\cos x \;
$
Complete step-by-step answer:
We have been given an equation:
$ \sin x = \cos x $ and we need to find the value of angle x in degrees.
This equation can be written as:
$ \sin x - \cos x = 0 $
Squaring both the sides, we get:
$
{\left( {\sin x - \cos x} \right)^2} = 0 \\
{\sin ^2}x + {\cos ^2}x - 2\sin x\cos x = 0 \\
1 - 2\sin x\cos x = 0\left( {\because {{\sin }^2}x + {{\cos }^2}x = 1} \right) \;
1 = 2\sin x\cos x \;
$
The value of double sine angle is given as:
$ \sin 2x = 2\sin x\cos x $
Substituting this value, we get:
$ \sin 2x = 1 $
The value of sin 90° is 1, so the above equation can be written as:
$
\sin 2x = \sin {90^\circ } \\
\Rightarrow 2x = {90^\circ } \\
\therefore x = {45^\circ } \;\
$
It is given that the angle is acute i.e. less than 90° which is also true for the angle obtained.
Therefore, if $ \sin x = \cos x $ and x is acute then the value of x is 45 degrees
So, the correct answer is “ 45° ”.
Note: We can also find the value of angle x by the following method, using the basic formula for tanx i.e. \[\dfrac{{\sin x}}{{\cos x}} = \tan x\]
Given equation: $ \sin x = \cos x $
Dividing both the sides by $ \cos x $ , we get:
\[
\dfrac{{\sin x}}{{\cos x}} = \dfrac{{\cos x}}{{\cos x}} \\
\tan x = 1 \\
\left( {\because \dfrac{{\sin x}}{{\cos x}} = \tan x} \right) \\
\]
The value of tan is 1 when the angle is equal to 45°, x can be calculated mathematically as:
$
\tan x = 1 \\
\Rightarrow x = {\tan ^{ - 1}}(1) \\
\therefore x = {45^\circ }\left( {\because \tan {{45}^\circ } = 1} \right) \;
$
Thus, we get the value of x as 45° by following every method.
The angles less than 90° are called acute angles and greater than that are called obtuse.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Trending doubts
Draw a diagram of nephron and explain its structur class 11 biology CBSE

Explain zero factorial class 11 maths CBSE

Chemical formula of Bleaching powder is A Ca2OCl2 B class 11 chemistry CBSE

Name the part of the brain responsible for the precision class 11 biology CBSE

The growth of tendril in pea plants is due to AEffect class 11 biology CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

