Answer

Verified

484.5k+ views

Hint:In order to solve this problem, we must use formulas of surface area and volume of Cuboid along with proper understanding of length, breadth and height of cuboid to get the required result.

Complete step-by-step answer:

In the question it is given the length(l) = 20cm, breadth(b) =15cm, height(h)=10cm of cuboid.

(A) Area of base ABCD = length(l) × breadth(b)

So on putting the values of length(l) & breadth(b)

=20×15

=300${\text{c}}{{\text{m}}^2}$.

(B) Surface area of its vertical faces

Here it is total 4 vertical surfaces, ABEF, BEHC, HCDG, AFGD

By observing the given figure, we can say that Surface area of its vertical faces ABEF, HCDG will be equal and will be the length(l) × height(h)

So Surface area of its vertical faces ABEF, HCDG = 2 (length(l) × height(h))

Similarly, by observing the given figure, we can say that Surface area of its vertical faces BEHC, AFGD will be equal and will be the breadth(b) × height(h)

So Surface area of its vertical faces BEHC, AFGD = 2 (breadth(b) × height(h))

So Total Surface area of its vertical faces =

2 (length(l) × height(h)) + 2 (breadth(b) × height(h))

=2(lh+bh)

So on putting all the values

= 2(20×10+15×10)

=2×350

=700 ${\text{c}}{{\text{m}}^2}$.

(C) we know that the Volume of cuboid is equal to length(l) × breadth(b) × height(h)

So on putting all the value

=20×15×10

=300×10

=3000 ${\text{c}}{{\text{m}}^3}$.

Note: Whenever we face such types of problems the key concept we have to remember is that always remember the formula of Surface area and volume of Cuboid which are stated above, then using those formulas calculate, whatever is asked in question.

Complete step-by-step answer:

In the question it is given the length(l) = 20cm, breadth(b) =15cm, height(h)=10cm of cuboid.

(A) Area of base ABCD = length(l) × breadth(b)

So on putting the values of length(l) & breadth(b)

=20×15

=300${\text{c}}{{\text{m}}^2}$.

(B) Surface area of its vertical faces

Here it is total 4 vertical surfaces, ABEF, BEHC, HCDG, AFGD

By observing the given figure, we can say that Surface area of its vertical faces ABEF, HCDG will be equal and will be the length(l) × height(h)

So Surface area of its vertical faces ABEF, HCDG = 2 (length(l) × height(h))

Similarly, by observing the given figure, we can say that Surface area of its vertical faces BEHC, AFGD will be equal and will be the breadth(b) × height(h)

So Surface area of its vertical faces BEHC, AFGD = 2 (breadth(b) × height(h))

So Total Surface area of its vertical faces =

2 (length(l) × height(h)) + 2 (breadth(b) × height(h))

=2(lh+bh)

So on putting all the values

= 2(20×10+15×10)

=2×350

=700 ${\text{c}}{{\text{m}}^2}$.

(C) we know that the Volume of cuboid is equal to length(l) × breadth(b) × height(h)

So on putting all the value

=20×15×10

=300×10

=3000 ${\text{c}}{{\text{m}}^3}$.

Note: Whenever we face such types of problems the key concept we have to remember is that always remember the formula of Surface area and volume of Cuboid which are stated above, then using those formulas calculate, whatever is asked in question.

Recently Updated Pages

Who among the following was the religious guru of class 7 social science CBSE

what is the correct chronological order of the following class 10 social science CBSE

Which of the following was not the actual cause for class 10 social science CBSE

Which of the following statements is not correct A class 10 social science CBSE

Which of the following leaders was not present in the class 10 social science CBSE

Garampani Sanctuary is located at A Diphu Assam B Gangtok class 10 social science CBSE

Trending doubts

Derive an expression for drift velocity of free electrons class 12 physics CBSE

Which are the Top 10 Largest Countries of the World?

Write down 5 differences between Ntype and Ptype s class 11 physics CBSE

The energy of a charged conductor is given by the expression class 12 physics CBSE

Fill the blanks with the suitable prepositions 1 The class 9 english CBSE

Derive an expression for electric field intensity due class 12 physics CBSE

How do you graph the function fx 4x class 9 maths CBSE

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths

Derive an expression for electric potential at point class 12 physics CBSE