Answer

Verified

482.4k+ views

Hint: Use the relation among centroid, circumcentre and orthocentre. Centroid is the point which divides the line joining orthocentre to circumcentre. Use the section formula to get centroid.

Complete step-by-step answer:

Here, we have given coordinates of circumcentre and orthocentre and we have to find coordinates of centroid. So, we need to use some relationship between all three of them.

As we know that centroid divides line joining orthocentre and circumcentre into 2: 1 ratio.

We have coordinates of

Orthocentre = (2,2)

Circumcentre = (5,5)

Let the coordinates of the centroid is (h,k).

So, we can represent the above now as;

Here, we have to find coordinates of G, which divides OC in 2: 1. So, we need to use sectional formulas to get coordinates of G.

Sectional formula is defined as if two points $A\left( {{x}_{1}},{{y}_{1}} \right)\text{ and }B\left( {{x}_{2}},{{y}_{2}} \right)$ are given on a line and any third point $C\left( {{x}_{3}},{{y}_{3}} \right)$ on the same line divides AB in ration m: n, then we can write point C as;

$\begin{align}

& {{x}_{3}}=\dfrac{m{{x}_{2}}+n{{x}_{1}}}{m+n} \\

& {{y}_{3}}=\dfrac{m{{y}_{2}}+n{{y}_{1}}}{m+n} \\

\end{align}$

Hence, coordinates of point C is $\left( \dfrac{m{{x}_{2}}+n{{x}_{1}}}{m+n},\dfrac{m{{y}_{2}}+n{{y}_{1}}}{m+n} \right)$

Now, coming to the question, we can use the sectional formula to get the centroid and where ratio m: n is given as (2: 1).

Therefore, we can use sectional formula to get G.

$\begin{align}

& G\left( h,k \right)=\left( \dfrac{2\times 5+1\times 2}{2+1},\dfrac{2\times 5+1\times 2}{2+1} \right) \\

& G\left( h,k \right)=\left( \dfrac{12}{3},\dfrac{12}{3} \right)=\left( 4,4 \right) \\

\end{align}$

Hence, coordinates of centroid id (4,4) if orthocentre and circumcentre are (2,2) and (5,5).

Option (E) is the correct option.

Note: One can go wrong while applying sectional formula. As one can apply formula as $\left( \dfrac{m{{x}_{1}}+n{{x}_{2}}}{m+n},\dfrac{m{{y}_{1}}+n{{y}_{2}}}{m+n} \right)$ which is wrong, so terms in sectional formula is very important.

One can take a triangle with coordinates as $\left( {{x}_{1}},{{y}_{1}} \right),\left( {{x}_{2}},{{y}_{2}} \right)\And \left( {{x}_{3}},{{y}_{3}} \right)$ and try to calculate $\left( {{x}_{1}},{{y}_{1}} \right),\left( {{x}_{2}},{{y}_{2}} \right)\And \left( {{x}_{3}},{{y}_{3}} \right)$ with the help of given orthocentre and circumcentre. But it will be a very long process and is not necessary for this question. So, we need to use the concept of relation between orthocentre, circumcentre and centroid. Centroid divides orthocentre and circumcentre in 2: 1 part.

Complete step-by-step answer:

Here, we have given coordinates of circumcentre and orthocentre and we have to find coordinates of centroid. So, we need to use some relationship between all three of them.

As we know that centroid divides line joining orthocentre and circumcentre into 2: 1 ratio.

We have coordinates of

Orthocentre = (2,2)

Circumcentre = (5,5)

Let the coordinates of the centroid is (h,k).

So, we can represent the above now as;

Here, we have to find coordinates of G, which divides OC in 2: 1. So, we need to use sectional formulas to get coordinates of G.

Sectional formula is defined as if two points $A\left( {{x}_{1}},{{y}_{1}} \right)\text{ and }B\left( {{x}_{2}},{{y}_{2}} \right)$ are given on a line and any third point $C\left( {{x}_{3}},{{y}_{3}} \right)$ on the same line divides AB in ration m: n, then we can write point C as;

$\begin{align}

& {{x}_{3}}=\dfrac{m{{x}_{2}}+n{{x}_{1}}}{m+n} \\

& {{y}_{3}}=\dfrac{m{{y}_{2}}+n{{y}_{1}}}{m+n} \\

\end{align}$

Hence, coordinates of point C is $\left( \dfrac{m{{x}_{2}}+n{{x}_{1}}}{m+n},\dfrac{m{{y}_{2}}+n{{y}_{1}}}{m+n} \right)$

Now, coming to the question, we can use the sectional formula to get the centroid and where ratio m: n is given as (2: 1).

Therefore, we can use sectional formula to get G.

$\begin{align}

& G\left( h,k \right)=\left( \dfrac{2\times 5+1\times 2}{2+1},\dfrac{2\times 5+1\times 2}{2+1} \right) \\

& G\left( h,k \right)=\left( \dfrac{12}{3},\dfrac{12}{3} \right)=\left( 4,4 \right) \\

\end{align}$

Hence, coordinates of centroid id (4,4) if orthocentre and circumcentre are (2,2) and (5,5).

Option (E) is the correct option.

Note: One can go wrong while applying sectional formula. As one can apply formula as $\left( \dfrac{m{{x}_{1}}+n{{x}_{2}}}{m+n},\dfrac{m{{y}_{1}}+n{{y}_{2}}}{m+n} \right)$ which is wrong, so terms in sectional formula is very important.

One can take a triangle with coordinates as $\left( {{x}_{1}},{{y}_{1}} \right),\left( {{x}_{2}},{{y}_{2}} \right)\And \left( {{x}_{3}},{{y}_{3}} \right)$ and try to calculate $\left( {{x}_{1}},{{y}_{1}} \right),\left( {{x}_{2}},{{y}_{2}} \right)\And \left( {{x}_{3}},{{y}_{3}} \right)$ with the help of given orthocentre and circumcentre. But it will be a very long process and is not necessary for this question. So, we need to use the concept of relation between orthocentre, circumcentre and centroid. Centroid divides orthocentre and circumcentre in 2: 1 part.

Recently Updated Pages

what is the correct chronological order of the following class 10 social science CBSE

Which of the following was not the actual cause for class 10 social science CBSE

Which of the following statements is not correct A class 10 social science CBSE

Which of the following leaders was not present in the class 10 social science CBSE

Garampani Sanctuary is located at A Diphu Assam B Gangtok class 10 social science CBSE

Which one of the following places is not covered by class 10 social science CBSE

Trending doubts

Harsha Charita was written by A Kalidasa B Vishakhadatta class 7 social science CBSE

Which are the Top 10 Largest Countries of the World?

Banabhatta wrote Harshavardhanas biography What is class 6 social science CBSE

Difference Between Plant Cell and Animal Cell

Fill the blanks with the suitable prepositions 1 The class 9 english CBSE

How do you graph the function fx 4x class 9 maths CBSE

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Why is there a time difference of about 5 hours between class 10 social science CBSE