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Question

Answers

(A). U’ = $\phi $

(B). $\phi $’ = U

(C). (A’)’ = A

(D). $A\cup A'=U$

(E). $A\cap A'=\phi $

Answer
Verified

Hint: First we will draw the Venn diagram with universal set U and subset A. Then we will solve this question by understanding the meaning of complement of a set, and then what is union and intersection of sets. We can check each option by trying to relate the concepts and find the sets. Then, we will be able to prove all the given options.

__Complete step-by-step answer:__

Universal set: The set containing all objects or elements and of which all other sets are subsets.

Complement of a set: Complement of a set A, denoted by A c, is the set of all elements that belongs to the universal set but does not belong to set A.

Union: The union (denoted by $\cup $ ) of a collection of sets is the set of all elements in the collection. It is one of the fundamental operations through which sets can be combined and related to each other.

Intersection: The intersection of two sets has only the elements common to both sets. If an element is in just one set it is not part of the intersection. The symbol is an upside down $\cap $ .

Here U is the universal set which is the area of total square and circle is the set A.

Let’s solve (a).

From this diagram we can see that U’ means the elements that are not present in U.

Hence, we get $U'=U-U=\phi $

Hence, it will be empty set which is $\phi $ .

Hence we have proved (a).

Now we will solve part (b).

$\phi '=U-\phi $

But $\phi $ is an empty set.

Therefore, $\phi '=U$ as the complement of empty set is universal set.

Hence (b) has been proved.

Now, for (c)

A’ = U – A

Now again taking complement,

(A’)’ = U – A’ = A

Hence we have proved (A’)’ = A.

From the diagram also we can see that it is true.

Now we will solve (d),

First we will look at A’,

Now the Venn diagram of $A\cup A'$ is:

From the diagram and definition of union we can see that $A\cup A'=U$.

Hence we have proved (d).

Now we will prove (e),

First we will look at A’,

From the diagram and definition of intersection we can see that $A\cap A'=\phi $.

Hence proved (e).

Note: Here we have used the definition of the given terms and also the Venn diagram to prove the above statements. Venn diagrams are very helpful to solve these types of questions. We must solve this question carefully using the concepts correctly instead of just proving them somehow. So, it is necessary to draw a Venn diagram for each option, apply the concepts and then prove them. We must not get confused between concepts of the union and intersection of sets.

Universal set: The set containing all objects or elements and of which all other sets are subsets.

Complement of a set: Complement of a set A, denoted by A c, is the set of all elements that belongs to the universal set but does not belong to set A.

Union: The union (denoted by $\cup $ ) of a collection of sets is the set of all elements in the collection. It is one of the fundamental operations through which sets can be combined and related to each other.

Intersection: The intersection of two sets has only the elements common to both sets. If an element is in just one set it is not part of the intersection. The symbol is an upside down $\cap $ .

Here U is the universal set which is the area of total square and circle is the set A.

Let’s solve (a).

From this diagram we can see that U’ means the elements that are not present in U.

Hence, we get $U'=U-U=\phi $

Hence, it will be empty set which is $\phi $ .

Hence we have proved (a).

Now we will solve part (b).

$\phi '=U-\phi $

But $\phi $ is an empty set.

Therefore, $\phi '=U$ as the complement of empty set is universal set.

Hence (b) has been proved.

Now, for (c)

A’ = U – A

Now again taking complement,

(A’)’ = U – A’ = A

Hence we have proved (A’)’ = A.

From the diagram also we can see that it is true.

Now we will solve (d),

First we will look at A’,

Now the Venn diagram of $A\cup A'$ is:

From the diagram and definition of union we can see that $A\cup A'=U$.

Hence we have proved (d).

Now we will prove (e),

First we will look at A’,

From the diagram and definition of intersection we can see that $A\cap A'=\phi $.

Hence proved (e).

Note: Here we have used the definition of the given terms and also the Venn diagram to prove the above statements. Venn diagrams are very helpful to solve these types of questions. We must solve this question carefully using the concepts correctly instead of just proving them somehow. So, it is necessary to draw a Venn diagram for each option, apply the concepts and then prove them. We must not get confused between concepts of the union and intersection of sets.

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