Answer
Verified
402.9k+ views
Hint- We cannot multiply any matrices. The conditions of the multiplication are:
The number of columns of the first matrix must equal the number of rows of the second matrix.
And the result will have the same number of rows as the first matrix and the same number of columns as the second matrix.
In general, to multiply \[m \times n\] a matrix by a \[n \times p\] matrix, the \[n\]’s must be the same, and the result is a \[m \times p\] matrix.
Multiply a number with a scalar number:
To multiply a number by a number is easy. Every element will be multiplied by the given scalar number.
Multiply a matrix by a matrix:
It is called the dot product. In this process, each element of the first row of the first matrix will be multiplied by the respective elements of the first column of the second matrix.
Complete step by step answer:
It is given that the matrix is,
\[A = \left( {\begin{array}{*{20}{c}}
3&{ - 3} \\
{ - 3}&3
\end{array}} \right)\]
Here, the given matrix \[A\] is of order \[2 \times 2\]. So, the matrix \[{A^2}\]will be also \[2 \times 2\] order.
So,
\[{A^2} = \left( {\begin{array}{*{20}{c}}
3&{ - 3} \\
{ - 3}&3
\end{array}} \right) \times \left( {\begin{array}{*{20}{c}}
3&{ - 3} \\
{ - 3}&3
\end{array}} \right)\]
As per the process, we will multiply each element of the first row of the first matrix by the respective elements of the first column of the second matrix.
\[{A^2} = \left( {\begin{array}{*{20}{c}}
{9 + 9}&{ - 9 - 9} \\
{ - 9 - 9}&{9 + 9}
\end{array}} \right)\]
Simplifying we get,
\[{A^2} = \left( {\begin{array}{*{20}{c}}
{18}&{ - 18} \\
{ - 18}&{18}
\end{array}} \right)\]
Now we will represent the matrix \[{A^2}\]in terms of \[A\].
So, we can write that,
\[{A^2} = \left( {\begin{array}{*{20}{c}}
{18}&{ - 18} \\
{ - 18}&{18}
\end{array}} \right) = 6\left( {\begin{array}{*{20}{c}}
3&{ - 3} \\
{ - 3}&3
\end{array}} \right)\]
So, we can write as,
\[{A^2} = 6A\]…. (1)
Again, it is given that, \[{A^2} = \lambda A\]…. (2)
Comparing equation (1) and (2) we get,
\[\lambda = 6\]
Hence, the value of \[\lambda = 6\].
Note – For the multiplication of matrices if the number of columns of the first matrix is not equal to the number of rows of the second matrix, the multiplication is not possible.
The number of columns of the first matrix must equal the number of rows of the second matrix.
And the result will have the same number of rows as the first matrix and the same number of columns as the second matrix.
In general, to multiply \[m \times n\] a matrix by a \[n \times p\] matrix, the \[n\]’s must be the same, and the result is a \[m \times p\] matrix.
Multiply a number with a scalar number:
To multiply a number by a number is easy. Every element will be multiplied by the given scalar number.
Multiply a matrix by a matrix:
It is called the dot product. In this process, each element of the first row of the first matrix will be multiplied by the respective elements of the first column of the second matrix.
Complete step by step answer:
It is given that the matrix is,
\[A = \left( {\begin{array}{*{20}{c}}
3&{ - 3} \\
{ - 3}&3
\end{array}} \right)\]
Here, the given matrix \[A\] is of order \[2 \times 2\]. So, the matrix \[{A^2}\]will be also \[2 \times 2\] order.
So,
\[{A^2} = \left( {\begin{array}{*{20}{c}}
3&{ - 3} \\
{ - 3}&3
\end{array}} \right) \times \left( {\begin{array}{*{20}{c}}
3&{ - 3} \\
{ - 3}&3
\end{array}} \right)\]
As per the process, we will multiply each element of the first row of the first matrix by the respective elements of the first column of the second matrix.
\[{A^2} = \left( {\begin{array}{*{20}{c}}
{9 + 9}&{ - 9 - 9} \\
{ - 9 - 9}&{9 + 9}
\end{array}} \right)\]
Simplifying we get,
\[{A^2} = \left( {\begin{array}{*{20}{c}}
{18}&{ - 18} \\
{ - 18}&{18}
\end{array}} \right)\]
Now we will represent the matrix \[{A^2}\]in terms of \[A\].
So, we can write that,
\[{A^2} = \left( {\begin{array}{*{20}{c}}
{18}&{ - 18} \\
{ - 18}&{18}
\end{array}} \right) = 6\left( {\begin{array}{*{20}{c}}
3&{ - 3} \\
{ - 3}&3
\end{array}} \right)\]
So, we can write as,
\[{A^2} = 6A\]…. (1)
Again, it is given that, \[{A^2} = \lambda A\]…. (2)
Comparing equation (1) and (2) we get,
\[\lambda = 6\]
Hence, the value of \[\lambda = 6\].
Note – For the multiplication of matrices if the number of columns of the first matrix is not equal to the number of rows of the second matrix, the multiplication is not possible.
Recently Updated Pages
Assertion The resistivity of a semiconductor increases class 13 physics CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
How do you arrange NH4 + BF3 H2O C2H2 in increasing class 11 chemistry CBSE
Is H mCT and q mCT the same thing If so which is more class 11 chemistry CBSE
What are the possible quantum number for the last outermost class 11 chemistry CBSE
Is C2 paramagnetic or diamagnetic class 11 chemistry CBSE
Trending doubts
Difference Between Plant Cell and Animal Cell
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Summary of the poem Where the Mind is Without Fear class 8 english CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
Write an application to the principal requesting five class 10 english CBSE
What organs are located on the left side of your body class 11 biology CBSE
What is the z value for a 90 95 and 99 percent confidence class 11 maths CBSE