If 6 g. of the urea dissolved in $90$ g. of boiling water. The vapour pressure of the solution is:
Answer
599.7k+ views
Hint: Rault’s law states that the vapor pressure of a solution of a non-volatile solute is equivalent to the vapor pressure of the pure solvent at that temperature multiplied by its mole fraction. It can be expressed by the following formula:
Vapour pressure \[P = P^\circ x,P^\circ = \] Boiling point of pure solvent and x being the mole fraction of the solvent.
Complete step by step answer:
We know,
${P^ \circ } = 760$mm of Hg
Mole fraction of solvent = $\dfrac{\text{moles of solvent}} {\text{total moles of solute and solvent}}$
To find the number of moles of urea (solute) and water (solvent):
Number of moles = $\dfrac{\text{given mass}} {\text{molar mass}}$
Given the mass of urea $ = 6g$
Molar mass of urea $ = 60g$
Moles of urea( ${n_1}$ )
$ = \dfrac{6}{{60}}$
$ = 0.1mole$
Given mass of water $ = 90g$
Molar mass of water $ = 18g$
Moles of water( ${n_2}$ )
$ = \dfrac{{90}}{{18}}$
$ = 5moles$
Now, to find the vapour pressure of solution we apply the formula:
\[P = P^\circ \dfrac{{{n_1}}}{{{n_1} + {n_2}}}\]
Substituting values in the formula:
$ = 760\left( {\dfrac{{0.1}}{{0.1 + 5}}} \right)$
$ = 760 \times 0.0196$
$ = 14.89Torr$
Now, $1Torr = 1mmHg$
Vapour pressure of solution \[ = 760 - 14.89 \approx 744.8\] mm of Hg
Note: Raoult’s law is quite similar to the ideal gas law. The only exception of Raoult’s law is that it applies to solutions too. The ideal gas law assumes the ideal behavior of gases in which the intermolecular forces that are present between dissimilar molecules is zero or non-existent. Whereas, Raoult’s law assumes that the intermolecular forces that exist between different molecules and similar molecules are equal.
Raoult’s law can be applied to non-ideal solutions too. However, this is done by incorporating several factors where we have to consider the interactions between molecules of different substances. An ideal solution is defined as one which obeys Raoult's Law.
Vapour pressure \[P = P^\circ x,P^\circ = \] Boiling point of pure solvent and x being the mole fraction of the solvent.
Complete step by step answer:
We know,
${P^ \circ } = 760$mm of Hg
Mole fraction of solvent = $\dfrac{\text{moles of solvent}} {\text{total moles of solute and solvent}}$
To find the number of moles of urea (solute) and water (solvent):
Number of moles = $\dfrac{\text{given mass}} {\text{molar mass}}$
Given the mass of urea $ = 6g$
Molar mass of urea $ = 60g$
Moles of urea( ${n_1}$ )
$ = \dfrac{6}{{60}}$
$ = 0.1mole$
Given mass of water $ = 90g$
Molar mass of water $ = 18g$
Moles of water( ${n_2}$ )
$ = \dfrac{{90}}{{18}}$
$ = 5moles$
Now, to find the vapour pressure of solution we apply the formula:
\[P = P^\circ \dfrac{{{n_1}}}{{{n_1} + {n_2}}}\]
Substituting values in the formula:
$ = 760\left( {\dfrac{{0.1}}{{0.1 + 5}}} \right)$
$ = 760 \times 0.0196$
$ = 14.89Torr$
Now, $1Torr = 1mmHg$
Vapour pressure of solution \[ = 760 - 14.89 \approx 744.8\] mm of Hg
Note: Raoult’s law is quite similar to the ideal gas law. The only exception of Raoult’s law is that it applies to solutions too. The ideal gas law assumes the ideal behavior of gases in which the intermolecular forces that are present between dissimilar molecules is zero or non-existent. Whereas, Raoult’s law assumes that the intermolecular forces that exist between different molecules and similar molecules are equal.
Raoult’s law can be applied to non-ideal solutions too. However, this is done by incorporating several factors where we have to consider the interactions between molecules of different substances. An ideal solution is defined as one which obeys Raoult's Law.
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Biology: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Class 12 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Trending doubts
Which is more stable and why class 12 chemistry CBSE

Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

What are the major means of transport Explain each class 12 social science CBSE

Sulphuric acid is known as the king of acids State class 12 chemistry CBSE

