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# Hydrogen and oxygen combine in the ratio of $1:8$ by mass to form water. What mass of oxygen gas would be required to react completely with $3g$ of hydrogen gas?

Last updated date: 22nd Jul 2024
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Hint: Here $1g$of hydrogen is completely reacting with $8$grams of oxygen. Because, the hydrogen and oxygen are combining in the ratio, $1:8$. And by the combining of hydrogen and oxygen, there is a formation of water. Hence, by using the ratio, we can calculate the required amount of oxygen gas to react completely with $3g$of hydrogen gas.

According to the law of constant proportions, the elements are present in a definite ratio by mass. Here, $1g$of hydrogen is completely reacting with $8$grams of oxygen. Because, the hydrogen and oxygen are combining in the ratio, $1:8$. And by the combining of hydrogen and oxygen, there is a formation of water.
Here, $1g$of hydrogen react with $8$grams oxygen
Hence, mass of oxygen gas would be required to react completely with $3g$of hydrogen gas is equal to, $3 \times 8 = 24g$.
Therefore, mass of oxygen gas would be required to react completely with $3g$of hydrogen gas is equal to$24g$. Thus, we can say that, according to the law of constant proportions, the elements are present in a definite ratio by mass.
We have to know that the mass of oxygen gas would be required to react completely with $3g$ of hydrogen gas is equal to, $24g$. According to the law of constant proportions, the chemical compounds are made up of elements and it is present in a fixed ratio by mass. There is no matter in the source. Water is a main example for this law, because it always contains a fixed mass ratio.