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How would you balance\[{\text{A}}{{\text{g}}_{\text{2}}}{\text{O}} \to {\text{Ag + }}{{\text{O}}_{\text{2}}}\]?

Last updated date: 13th Jul 2024
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Hint: As we know that in chemistry, equations play a major role. In the reaction three things are main. There are reactants, products and reaction conditions. The reactants are always on the left side of the equation. If more than one reactant in the equation means by using plus sign. The products are always on the right side of the reaction. Something here also follows. More than one product by using plus sign. In between reactant products are used arrows to find the reaction direction in the equation.

Complete answer:
In chemistry, balances the chemical equation means,
We adjust the number moles of reactant and product used to attain an equal number of the same atom in reactant and product in the given chemical reaction.
The given chemical reaction is,
\[{\text{A}}{{\text{g}}_{\text{2}}}{\text{O}} \to {\text{Ag + }}{{\text{O}}_{\text{2}}}\]
On the reactant side two silver atoms and one oxygen atom, but on the product side one silver atom and two oxygen atoms.
We want to balance the given chemical reaction, increase the mole of silver oxide from one to two in the reactant side and increase the moles of silver from one to four.
\[{\text{2A}}{{\text{g}}_{\text{2}}}{\text{O}} \to 4{\text{Ag + }}{{\text{O}}_{\text{2}}}\]
Now the given chemical reaction is balanced.

We must have to know that in balanced chemical reaction wise, we predict the side product of the reaction. In some cases we are not able to attain balance by changing the mole. In that case we use the number of countable ions in the product and reactant side of the chemical reaction. In chemistry, redox reaction is one of the types of major reactions. In this redox reaction two methods are used to attain the balanced chemical reaction. There are ion-electron methods and the oxidation number method.