How do you solve $x+\dfrac{1}{4}x=30$ ?
Answer
572.4k+ views
Hint: For answering this question we are asked to solve the given equation $x+\dfrac{1}{4}x=30$ and find the value of the variable $x$ . For solving that we will make some transformations like shifting from right hand to left hand side and vice versa and basic arithmetic simplifications like addition and subtraction then we need to conclude the value of the unknown variable $x$
Complete answer:
Now considering from the question we have been asked to solve the given equation $x+\dfrac{1}{4}x=30$ and derive the value of unknown variable $x$ .
Firstly we will observe the given equation and bring all the terms containing the unknown variable $x$ one side and the other terms on the other side of the equation.
If we observe the given equation carefully it is already arranged similarly.
Now by performing basic arithmetic simplifications that is addition in this case we will get the equation reduced to $\Rightarrow \dfrac{5}{4}x=30$ .
Now we will transform the $4$ from the left hand side to the right hand side after this transformation we will have $\Rightarrow 5x=4\times 30$ .
Now we will perform the multiplication arithmetic operation involved in the right hand side of the equation after that we will have $\Rightarrow 5x=120$ .
Now after this we will transform $5$ from the left hand side to the right hand side then we will have $\Rightarrow x=\dfrac{120}{5}$ .
By further performing the division operation for the terms involved in the right hand side we will have $\Rightarrow x=24$ .
Therefore we can conclude that the value of $x$ in $x+\dfrac{1}{4}x=30$ is $24$ .
Note:
We should be sure with our calculations while solving this question and the transformations and basic arithmetic simplifications we make. Similarly we can solve the same type of equations for example $p+\dfrac{1}{3}p=4\Rightarrow \dfrac{4}{3}p=4\Rightarrow p=3$ . It’s better to verify the value we got before finalising the answer here verification means substituting the value we got in the equation $x+\dfrac{1}{4}x=30$ in the place of $x$ . As we had got $x=24$ by substituting it in the left hand side we will have,
$\begin{align}
& 24+\dfrac{1}{4}\left( 24 \right) \\
& \Rightarrow 24+6 \\
& \Rightarrow 30 \\
\end{align}$
which is equal to the value in the right hand side.
Complete answer:
Now considering from the question we have been asked to solve the given equation $x+\dfrac{1}{4}x=30$ and derive the value of unknown variable $x$ .
Firstly we will observe the given equation and bring all the terms containing the unknown variable $x$ one side and the other terms on the other side of the equation.
If we observe the given equation carefully it is already arranged similarly.
Now by performing basic arithmetic simplifications that is addition in this case we will get the equation reduced to $\Rightarrow \dfrac{5}{4}x=30$ .
Now we will transform the $4$ from the left hand side to the right hand side after this transformation we will have $\Rightarrow 5x=4\times 30$ .
Now we will perform the multiplication arithmetic operation involved in the right hand side of the equation after that we will have $\Rightarrow 5x=120$ .
Now after this we will transform $5$ from the left hand side to the right hand side then we will have $\Rightarrow x=\dfrac{120}{5}$ .
By further performing the division operation for the terms involved in the right hand side we will have $\Rightarrow x=24$ .
Therefore we can conclude that the value of $x$ in $x+\dfrac{1}{4}x=30$ is $24$ .
Note:
We should be sure with our calculations while solving this question and the transformations and basic arithmetic simplifications we make. Similarly we can solve the same type of equations for example $p+\dfrac{1}{3}p=4\Rightarrow \dfrac{4}{3}p=4\Rightarrow p=3$ . It’s better to verify the value we got before finalising the answer here verification means substituting the value we got in the equation $x+\dfrac{1}{4}x=30$ in the place of $x$ . As we had got $x=24$ by substituting it in the left hand side we will have,
$\begin{align}
& 24+\dfrac{1}{4}\left( 24 \right) \\
& \Rightarrow 24+6 \\
& \Rightarrow 30 \\
\end{align}$
which is equal to the value in the right hand side.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

