Answer
Verified
417.6k+ views
Hint: First of all take the given equation and move all the terms without “y” on the right hand side of the equation and simplify the equation using basic mathematics rules making the subject “y” to get the required resultant value.
Complete step-by-step solution:
Take the given equation.
$8x - 8y = 5$
Change all the terms from the left hand side to the right hand side and the terms from the right hand side to the left side. The above equation can be re-written as-
$5 = 8x - 8y$
Move constantly from the left to the right and the term with the variable “y” from the right hand side to the left hand side. When you move any term from one side to another, then the sign of the term also changes. Positive terms become negative and the negative term becomes positive.
$8y = 8x - 5$
Term multiplicative on one side if moved to the opposite side, then it goes to the denominator.
$ \Rightarrow y = \dfrac{{8x - 5}}{8}$
This is the required solution.
Additional Information: Always remember that when we expand the brackets or open the brackets, sign outside the bracket is most important. If there is a positive sign outside the bracket then the values inside the bracket does not change and if there is a negative sign outside the bracket then all the terms inside the bracket changes. Positive terms change to the negative and the negative term changes to the positive.
Note: Always remember that when you move any term from one side to another, the sign of the term also changes. Positive term becomes the negative term and vice-versa. Be careful about the sign convention.
Complete step-by-step solution:
Take the given equation.
$8x - 8y = 5$
Change all the terms from the left hand side to the right hand side and the terms from the right hand side to the left side. The above equation can be re-written as-
$5 = 8x - 8y$
Move constantly from the left to the right and the term with the variable “y” from the right hand side to the left hand side. When you move any term from one side to another, then the sign of the term also changes. Positive terms become negative and the negative term becomes positive.
$8y = 8x - 5$
Term multiplicative on one side if moved to the opposite side, then it goes to the denominator.
$ \Rightarrow y = \dfrac{{8x - 5}}{8}$
This is the required solution.
Additional Information: Always remember that when we expand the brackets or open the brackets, sign outside the bracket is most important. If there is a positive sign outside the bracket then the values inside the bracket does not change and if there is a negative sign outside the bracket then all the terms inside the bracket changes. Positive terms change to the negative and the negative term changes to the positive.
Note: Always remember that when you move any term from one side to another, the sign of the term also changes. Positive term becomes the negative term and vice-versa. Be careful about the sign convention.
Recently Updated Pages
what is the correct chronological order of the following class 10 social science CBSE
Which of the following was not the actual cause for class 10 social science CBSE
Which of the following statements is not correct A class 10 social science CBSE
Which of the following leaders was not present in the class 10 social science CBSE
Garampani Sanctuary is located at A Diphu Assam B Gangtok class 10 social science CBSE
Which one of the following places is not covered by class 10 social science CBSE
Trending doubts
Which are the Top 10 Largest Countries of the World?
How do you graph the function fx 4x class 9 maths CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
The only snake that builds a nest is a Krait b King class 11 biology CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
In Indian rupees 1 trillion is equal to how many c class 8 maths CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
Why is there a time difference of about 5 hours between class 10 social science CBSE
Which places in India experience sunrise first and class 9 social science CBSE