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How do you solve for y in $8x - 8y = 5$?

seo-qna
Last updated date: 16th Jun 2024
Total views: 372.6k
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Answer
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372.6k+ views
Hint: First of all take the given equation and move all the terms without “y” on the right hand side of the equation and simplify the equation using basic mathematics rules making the subject “y” to get the required resultant value.

Complete step-by-step solution:
Take the given equation.
$8x - 8y = 5$
Change all the terms from the left hand side to the right hand side and the terms from the right hand side to the left side. The above equation can be re-written as-
$5 = 8x - 8y$
Move constantly from the left to the right and the term with the variable “y” from the right hand side to the left hand side. When you move any term from one side to another, then the sign of the term also changes. Positive terms become negative and the negative term becomes positive.
$8y = 8x - 5$
Term multiplicative on one side if moved to the opposite side, then it goes to the denominator.
$ \Rightarrow y = \dfrac{{8x - 5}}{8}$
This is the required solution.

Additional Information: Always remember that when we expand the brackets or open the brackets, sign outside the bracket is most important. If there is a positive sign outside the bracket then the values inside the bracket does not change and if there is a negative sign outside the bracket then all the terms inside the bracket changes. Positive terms change to the negative and the negative term changes to the positive.

Note: Always remember that when you move any term from one side to another, the sign of the term also changes. Positive term becomes the negative term and vice-versa. Be careful about the sign convention.