How do you solve $\dfrac{9}{8}=\dfrac{k+6}{6}$?
Answer
573k+ views
Hint: The equation given in the above question is a linear equation in one variable, that is k. The question says that we have to solve the given equation in k. In other words, we have to find the values of k which will satisfy the given equation. Try to find the value of k by performing some mathematical operations.
Complete step-by-step solution:
The given equation says that $\dfrac{9}{8}=\dfrac{k+6}{6}$.
Let us analyse the given equation and check what we can do to find the value of k that satisfies the given equation.
The first thing that we can do here is get rid of the fraction present in the equation.
This can be done by multiplying the terms.
Or we can also multiply both the sides of the equation by a factor of $6\times 8$.
Therefore, the above equation can be written as $9\times 6=8(k+6)$.
With this, the equation can be further simplified to $9\times 6=8k+(8\times 6)$.
$\Rightarrow 54=8k+48$
$\Rightarrow 8k=54-48=6$
$\Rightarrow k=\dfrac{6}{8}$
With this, we get that $k=\dfrac{6}{8}$
Therefore, the solution of the given equation is $k=\dfrac{6}{8}$ or we can also say that the value $k=\dfrac{6}{8}$ satisfies the given equation.
Note: There are many ways in which we can solve this question. We can also directionally add the two fractions on the left hand side of the equation and calculate the value of k. However, students must note that the number of solutions to a given equation in one variable is always less than or equal to the degree of the polynomial in the given equation.
Complete step-by-step solution:
The given equation says that $\dfrac{9}{8}=\dfrac{k+6}{6}$.
Let us analyse the given equation and check what we can do to find the value of k that satisfies the given equation.
The first thing that we can do here is get rid of the fraction present in the equation.
This can be done by multiplying the terms.
Or we can also multiply both the sides of the equation by a factor of $6\times 8$.
Therefore, the above equation can be written as $9\times 6=8(k+6)$.
With this, the equation can be further simplified to $9\times 6=8k+(8\times 6)$.
$\Rightarrow 54=8k+48$
$\Rightarrow 8k=54-48=6$
$\Rightarrow k=\dfrac{6}{8}$
With this, we get that $k=\dfrac{6}{8}$
Therefore, the solution of the given equation is $k=\dfrac{6}{8}$ or we can also say that the value $k=\dfrac{6}{8}$ satisfies the given equation.
Note: There are many ways in which we can solve this question. We can also directionally add the two fractions on the left hand side of the equation and calculate the value of k. However, students must note that the number of solutions to a given equation in one variable is always less than or equal to the degree of the polynomial in the given equation.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

