Courses
Courses for Kids
Free study material
Offline Centres
More
Store Icon
Store

How do you graph $r=3\cos \theta $?

seo-qna
Last updated date: 20th Jun 2024
Total views: 375.9k
Views today: 7.75k
Answer
VerifiedVerified
375.9k+ views
Hint: We explain the number of ways the position of a point or equation can be expressed in different forms. To form the graph of $r=3\cos \theta $, we need to find its rectangular form. We also explain the ways the representation works for polar and cartesian form. Then we convert the given equation into rectangular form using the relations $x=r\cos \theta ;y=r\sin \theta $.

Complete step-by-step solution:
There are always two ways to represent any point equation in our general 2-D and 3-D surfaces. One being the polar form and other one being the cartesian form. The other name of the cartesian form is rectangular form.
In case of polar form, we use the distance and the angle from the origin to get the position of the point or curve.
The given equation $r=3\cos \theta $ is a representation of the polar form. r represents the distance and $\theta $ represents the angle.
In case of rectangular form, we use the coordinates from the origin to get the position of the point or curve. For two dimensional things we have X-Y and for three dimensional things we have X-Y-Z. We take the perpendicular distances from the axes.
We need to convert the given equation $r=3\cos \theta $ into the rectangular form.
The relation between these two forms in two-dimensional is
$x=r\cos \theta ;y=r\sin \theta ;{{x}^{2}}+{{y}^{2}}={{r}^{2}}$.
From the relations we get $\cos \theta =\dfrac{x}{r}$.
We now replace the value of $\cos \theta =\dfrac{x}{r}$ in the equation $r=3\cos \theta $ to get
\[\begin{align}
  & r=3\cos \theta \\
 & \Rightarrow r=3\left( \dfrac{x}{r} \right) \\
 & \Rightarrow {{r}^{2}}=3x \\
\end{align}\]
We now replace the value of ${{x}^{2}}+{{y}^{2}}={{r}^{2}}$ for the equation.
The revised equation becomes \[\left( {{x}^{2}}+{{y}^{2}} \right)=3x\]. This is an equation of a circle.
seo images


Note: In case of points for cartesian form we use x and y coordinates as $\left( x,y \right)$ to express their position in the cartesian plane. The distance from origin is $r=\sqrt{{{x}^{2}}+{{y}^{2}}}$. This r represents the distance in polar form.