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# How do you graph $y = - 3x + 5$ using slope intercept form?

Last updated date: 22nd Jun 2024
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Hint: In this question, we draw a graph using the above equation. The equation which is given above is a straight line equation. In the above equation is an independent variable and y is a dependent variable. For drawing the graph, first we calculate the points and points are calculated as we put the value of x like $\left( {0,\;1,\;2,.......} \right)$ in the above equation and then find the value of y. then we draw the graph by using these points.

Now we come to question, in the question the straight-line equation is given as below.
$\Rightarrow y = - 3x + 5$
The slope is $m = - 3$.
Now we find the points from the above equation.
We put the value of $x = 0$ in the above equation, and then we find the value of y.
$y = - 3 \times 0 + 5 \\ y = 5 \\$
The value of y is $= 5$
Then the point is $\left( {0,\;5} \right)$.
Now, we put the value of $x = 1$in the above equation, and then find the value of y.
$y = - 3 \times 1 + 5 \\ y = 2 \\$
The value of y is $= 2$
Then the point is $\left( {1,\;2} \right)$.
Then, we put $x = 2$ in the above equation then $y = - 1$. Then the point is $\left( {2,\; - 1} \right)$.
Hence, we calculate the same for other points.
Now we draw the graph by using the points.
The points are $\left( {\left( {0,\;5} \right),\left( {1,\;2} \right),\left( {2,\; - 1} \right)} \right)$.
Therefore, the graph is drawn as below.

Note:
In this question, we use the word slope intercept form. Slope intercept form is defined as the form of straight-line equation. Slope intercept form is represented as below.
$\Rightarrow y = mx + c$
Where,
$m =$ Slope
$c =$ It is y intercept
And x and y are the variable. Where x is an independent variable and y is a dependent variable. When we put the value of x then we find the value of y.
draw the graph.