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**Hint:**Suppose an equation of straight line to be \[y=ax+b\]. We can draw the graph of \[y=ax+b\] from the simple graph \[y=x\]. We need to modify the \[y=x\] graph by shifting and scaling methods. It is a better idea to modify the graph of \[y=x\] in such a manner that we get the required graph by going from left side to right side of the equation \[y=\dfrac{3}{2}x-3\].

**Complete step by step answer:**

As per the given question, we need to graph a straight line which is given by the equation \[y=\dfrac{3}{2}x-3\].

A straight line can be traced out on the cartesian plane by just two points lying on it. We can also use a third point for sort of check. It is very simple to graph the \[y=x\] line as it is symmetric to both x and y axes.

The graph of \[y=x\] is as shown in below figure:

If we go from left hand side to right hand side of the equation \[y=\dfrac{3}{2}x-3\], it is clear that we need to first scale the \[y=x\] graph by a factor \[\dfrac{3}{2}\]. Then we get \[y=\dfrac{3}{2}x\].

And the graph of \[y=\dfrac{3}{2}x\] is as shown in the below figure:

Now, we need to shift the \[y=\dfrac{3}{2}x\] graph right hand side by 3 units to get the required straight line \[y=\dfrac{3}{2}x-3\]. And the graph of \[y=\dfrac{3}{2}x-3\] is shown in the below figure:

Since we need to plot \[y\underline{>}\dfrac{3}{2}x-3\] we have to shade the part above the line. Thus, it looks like,

\[\therefore \] we have to compress \[y=x\] by \[\dfrac{3}{2}\] and then shift it to the right hand side by 3 units and shade the part above the line to get the desired plot \[y\underline{>}\dfrac{3}{2}x-3\].

**Note:**

We can trace the graph of \[y\underline{>}\dfrac{3}{2}x-3\] by substitution by any two random values of x and joining the two random variables with a line. we have to check which part to be shaded depending on the sign given in the problem.

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