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# How many grams of silicon is present in $\;35$ gram atom of silicon?

Last updated date: 10th Sep 2024
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Hint:To calculate the amount of silicon present in $\;35$ gram atoms we have to use the mole concept and calculate the number of atoms with the help of the average atomic weight of silicon atom.The atomic number of silicon is $14$. The average atomic weight of silicon is $28.085\,amu$.

In chemistry One mole is defined as the amount of a substance that has exactly$6.02214076\,\, \times {10^{23}}$ ‘elementary entities’ of that substance. The number $6.02214076\,\, \times {10^{23}}$ is called the Avogadro constant and is often represented by the symbol. The elementary entities that are represented in moles could be atoms, molecules, monatomic or polyatomic ions.
One mole of silicon weighs $28.085\,amu$. Gram atoms are also known as moles
Now grams of silicon present in $35gm$ atoms of silicon are $28.085 \times 35 = 980$
Hence, $35gm$ atoms of silicon contains $980gm$ of silicon.