Courses
Courses for Kids
Free study material
Offline Centres
More
Store

# How many grams are in $5.7{\text{ }}mol$ potassium permanganate?

Last updated date: 13th Jun 2024
Total views: 371.7k
Views today: 9.71k
Verified
371.7k+ views
Hint: Potassium permanganate chemical formula is $KMn{O_4}$ . $KMn{O_4}$ is a potassium salt of manganic acid. Likewise known as the permanganate of potash, it has various other names for instance chameleon mineral, Condy's crystals and hypermangan.
Potassium permanganate is an ionic compound containing of a potassium cation $\left( {{K^ + }} \right)$ and permanganate anion $\left( {Mn{O_4}^ - } \right)$

We take up you are converting between moles $KMn{O_4}$ and gram. You can view more specifics on each amount unit molecular weight of $KMn{O_4}$ or grams This compound is also acknowledged as Potassium Permanganate. The SI base unit for quantity of substance is the mole.
$1{\text{ }}mole$ is equal to $\;1{\text{ }}moles$ $KMn{O_4}$ , or $158.033949{\text{ }}grams$
The compulsory mass is simply the product, moles × molar mass,
i.e. $5.7 \cdot mol{\text{ }} \times {\text{ }}158.034 \cdot g \cdot mo{l^{ - 1}} = {\text{ }}900 \cdot g$
There are almost $900 \cdot g\;$ in a $5.7\;$ molar quantity of $KMn{O_4}$ .

$KMn{O_4}$ is solvable in acetone, water, pyridine, methanol and acetic acid. It is also freely soluble in inorganic solvents.
Note: The oxidation state of manganese in this salty is $+ 7$ .