Given the equation 3x + y = -4, how do you solve for y?
Answer
604.2k+ views
Hint: To solve the given equation to y, we have to check the type of the equation as whether it is a linear equation or quadratic equation or any other. They make sure to get all the terms with y to the LHS and the remaining terms to the RHS so that we can take y common from the terms which contain y, then make sure to keep only y in the LHS and take all the remaining terms to the RHS.
Complete step by step solution:
Here the given equation is as below,
3x + y = -4
Subtract 3x from both sides i.e. LHS and RHS
\[\Rightarrow \] 3x + y – 3x = -4 – 3x
+3x and -3x gets cancelled from the LHS, so we get,
\[\Rightarrow \] + y = - 4 – 3x
The above equation is now solved for y as we can see y in the LHS and so we the required answer for the given question as mentioned below,
\[\Rightarrow \] y = - 4 – 3x.
Note: Here it is important for us to identify all the terms with y in the given quadratic equation to separate them from the other terms to make sure that we take y common from them. It is also necessary for us to keep only y in the LHS and all other terms to the RHS. Students should be aware of the signs while taking the terms from LHS to RHS and vice versa.
Complete step by step solution:
Here the given equation is as below,
3x + y = -4
Subtract 3x from both sides i.e. LHS and RHS
\[\Rightarrow \] 3x + y – 3x = -4 – 3x
+3x and -3x gets cancelled from the LHS, so we get,
\[\Rightarrow \] + y = - 4 – 3x
The above equation is now solved for y as we can see y in the LHS and so we the required answer for the given question as mentioned below,
\[\Rightarrow \] y = - 4 – 3x.
Note: Here it is important for us to identify all the terms with y in the given quadratic equation to separate them from the other terms to make sure that we take y common from them. It is also necessary for us to keep only y in the LHS and all other terms to the RHS. Students should be aware of the signs while taking the terms from LHS to RHS and vice versa.
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