Question

# Give the major product the following reaction?A.B.C.D.None of these

Hint: The reaction given in the question is an example of Friedel-Crafts alkylation. Friedel–Crafts alkylation involves the alkylation of an aromatic ring with an alkyl halide using a strong lewis acid. Now, you should use this to reach the correct answer.

To solve this question first we need to identify the type of reaction. Here we can see an aromatic ring (phenol) reacting with an alkyl halide in the presence of $AlCl_{ 3 }$, which is a lewis acid and works as a catalyst. Hence, we can categorize it under Friedel–Crafts alkylation.
A Lewis acid catalyst such as $AlCl_{ 3 }$ is employed in this reaction to form a carbocation by facilitating the removal of the halide. The resulting carbocation undergoes a rearrangement before proceeding with the alkylation reaction.
Now, let’s move to the question. We have phenol or we can say benzene with -OH group attached to it. This -OH has two lone pairs that it will donate one to the empty orbitals of $AlCl_{ 3 }$, meaning phenol will work as a base and will form a complex salt. This salt will not undergo any further reaction.