Give one chemical test as an evidence to show that $[Co{(N{H_3})_5}Cl]S{O_4}$ and $[Co{(N{H_3})_5}(S{O_4})]Cl$ are ionisation isomers.
Answer
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Hint: Transition metals tend to form complex compounds which are different in properties than the normal compounds. They are composed of the ionisation sphere and the inner sphere. The ionisation sphere is the sphere in which the elements are not so closely bound and they may be ionised upon dissolution. The isomers with different ionisation spheres are called ionisation isomers.
Complete step by step answer:
Ionisation isomers have the property as to when they are dissolved in water, they readily ionize to give different ions. These ions then have different reactions with different reagents and thus form products that are more or less different. Some of the reactions that these isomers can show differently can be shown as,
Let the above compounds be reacted to the barium ions. They surely react differently and produce different products that can be seen in a couple of reactions below,
$[Co{(N{H_3})_5}Cl]S{O_4} + B{a^{ + 2}}\xrightarrow[{}]{}BaS{O_4} \downarrow $
$[Co{(N{H_3})_5}S{O_4}]Cl + B{a^{ + 2}}\xrightarrow[{}]{}No{{ Reaction}}$
In the first reaction, the compound forms a white precipitate of barium sulphate, while in the second reaction the compound doesn’t react with the ions and no reaction occurs.
Another set of reactions involved the reaction of these compounds with silver ions. The reactions of these compounds can be depicted as below,
$[Co{(N{H_3})_5}Cl]S{O_4} + A{g^ + }\xrightarrow{{}}No{{ Reaction}}$
$[Co{(N{H_3})_5}S{O_4}]Cl + A{g^ + }\xrightarrow[{}]{}AgCl \downarrow $
We can see that on the reaction with the silver ion one of the compounds doesn’t undergo a reaction while the other forms a white precipitate of silver chloride.
All these reactions can be used to show the different nature of these complex compounds and thus can be used to show these are ionisation isomers.
Note: The elements in the periodic table are classified in the form of blocks, groups, and periods based on the properties that they show. The change in the group or the period shows the change in the number of shells and the number of electrons in the shell.
The elements in-between groups 3 through 12 are called the transition elements. These contain the elements that own more of the metallic properties like iron, copper, etc. They are the only elements in the periodic table to produce the magnetic field.
Complete step by step answer:
Ionisation isomers have the property as to when they are dissolved in water, they readily ionize to give different ions. These ions then have different reactions with different reagents and thus form products that are more or less different. Some of the reactions that these isomers can show differently can be shown as,
Let the above compounds be reacted to the barium ions. They surely react differently and produce different products that can be seen in a couple of reactions below,
$[Co{(N{H_3})_5}Cl]S{O_4} + B{a^{ + 2}}\xrightarrow[{}]{}BaS{O_4} \downarrow $
$[Co{(N{H_3})_5}S{O_4}]Cl + B{a^{ + 2}}\xrightarrow[{}]{}No{{ Reaction}}$
In the first reaction, the compound forms a white precipitate of barium sulphate, while in the second reaction the compound doesn’t react with the ions and no reaction occurs.
Another set of reactions involved the reaction of these compounds with silver ions. The reactions of these compounds can be depicted as below,
$[Co{(N{H_3})_5}Cl]S{O_4} + A{g^ + }\xrightarrow{{}}No{{ Reaction}}$
$[Co{(N{H_3})_5}S{O_4}]Cl + A{g^ + }\xrightarrow[{}]{}AgCl \downarrow $
We can see that on the reaction with the silver ion one of the compounds doesn’t undergo a reaction while the other forms a white precipitate of silver chloride.
All these reactions can be used to show the different nature of these complex compounds and thus can be used to show these are ionisation isomers.
Note: The elements in the periodic table are classified in the form of blocks, groups, and periods based on the properties that they show. The change in the group or the period shows the change in the number of shells and the number of electrons in the shell.
The elements in-between groups 3 through 12 are called the transition elements. These contain the elements that own more of the metallic properties like iron, copper, etc. They are the only elements in the periodic table to produce the magnetic field.
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