For narrating some incidents A speaks truth in $75\% $ cases and B in $80\% $ of the cases. In narrating some cases both A and B are likely to contradict each other. What is the percentage of the cases in which they both likely contradict each other, narrating the same incident?
(A) $25\% $
(B) $40\% $
(C) $35\% $
(D) $10\% $

Question

For narrating some incidents A speaks truth in $75\% $ cases and B in $80\% $ of the cases. In narrating some cases both A and B are likely to contradict each other. What is the percentage of the cases in which they both likely contradict each other, narrating the same incident?
(A) $25\% $
(B) $40\% $
(C) $35\% $
(D) $10\% $

Vedantu Content Team · Accepted Answer

Hint:In this we apply the probability of happening an event and not happening of that particular event. So, the probability of A speaking truth is P (A) = $75\% $or $$\dfrac{3}{4}$$and not speaking truth or lie $P(\overline A )$ = $25\% $ or$\dfrac{1}{4}$. Similarly the probability of B speaking truth is P (B) = $80\% $ or $\dfrac{4}{5}$and not speaking truth is $P(\overline {B)} $= $20\% $ or$\dfrac{1}{5}$. In case of contradiction with each other is when A speaks truth and B speaks lie or A speaks lie and B speaks truth. For finding the probability we add both the situation and find the percentage.Complete step-by-step answer:Let A be Event that speaks the truth and B be Event that speaks the truthSo, the probability of A speaking truth P(A)= $75\% $=$\dfrac{{75}}{{100}} = \dfrac{3}{4}$The probability of B speaking truth P(B)= $80\% $=$\dfrac{{80}}{{100}} = \dfrac{4}{5}$We know $P(A)+P(\overline A )=1$ Hence,Probability of A not speaking truth $P(\overline A )$= $1 - \dfrac{3}{4} = \dfrac{1}{4}$Probability of B not speaking truth $P(\overline {B)} $ = $1 - \dfrac{4}{5}=\dfrac{1}{5}$Now, A and B contradict each other=[A speaks truth and B speaks lie] or [A speaks lie and B speaks truth]We will add both situation=  $P(A) \times P(\overline B ) + P(\overline A ) \times P(B)$=$$(\dfrac{3}{4} \times \dfrac{1}{5}) + (\dfrac{1}{4} \times \dfrac{4}{5})$$=$\dfrac{3}{{20}} + \dfrac{4}{{20}}$=$\dfrac{7}{{20}}$For percentage we multiply $\dfrac{7}{{20}}$ by $100\% $=$(\dfrac{7}{{20}} \times 100)\% $=$35\% $So, the case when A and B contradicts is $35\% $.The correct answer is C=$35\% $.So, the correct answer is “Option C”.Note:When there is a case of contradiction we must consider both the cases i.e. probability of happening of the event and probability not happening of the event. The probability of the event lies between 0 and 1, where 0 and 1 are included.

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