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# For $0.3g$ of an acid is neutralized by $40c{{m}^{3}}$ of $0.125N\text{ }NaOH.$ Equivalent mass of the acid is:A.$60.$B.$45.$C.$30.$D.$63.$

Last updated date: 26th Feb 2024
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Hint: We know that in order to find the equivalent weight of a given compound we will use the formula of equivalent weight as it is the ratio of molecular mass to the number of replaceable hydrogen. By the use of a general formula and the atomic masses of elements from the periodic table we will solve this problem.

Number of equivalent of acid $=$ Number of equivalent of base $\dfrac{N\times V}{1000}\text{ }=\text{ }\dfrac{0.125\times 40}{1000}\text{ }=\text{ }0.005$
thus, 0.005 equivalents of acid weight $=\text{ }0.3$ and one equivalent of acid weight $=\text{ }\dfrac{0.3}{0.005}\text{ }=\text{ }\dfrac{3}{10}\times \dfrac{1000}{5}\text{ }=\text{ }60g$
Therefore, $0.3g$ of an acid is neutralized by $40c{{m}^{3}}$ of $0.125N\text{ }NaOH.$ Equivalent mass of the acid is $60g.$
Remember that Equivalent weight is the weight of one equivalent which is the weight of a given substance which combines with or displaces a fixed quantity of another. An element's equivalent weight is the mass which combines or displaces $1.008$ grams of hydrogen. The main use of sulfuric acid is in fertilizer production, e.g., lime superphosphate and ammonium sulfate. It is commonly used even in the processing of chemicals and other acids.