Answer
Verified
423.3k+ views
Hint: First check whether the series is in A.P or not by finding the difference between them. After this use formula to find the sum of first $21$ terms. You will get the answer.
Complete step-by-step answer:
Arithmetic Progression (A.P) is a sequence of numbers in a particular order. If we observe in our regular lives, we come across progression quite often. For example, roll numbers of a class, days in a week, or months in a year. This pattern of series and sequences has been generalized in maths as progressions. Let us learn here AP definition, important terms such as common difference, the first term of the series, nth term and sum of nth term formulas along with solved questions based on them.
It is a mathematical sequence in which the difference between two consecutive terms is always a constant and it is abbreviated as A.P.
The fixed number that must be added to any term of an A.P to get the next term is known as the common difference of the A.P.
An arithmetic sequence or progression is defined as a sequence of numbers in which for every pair of consecutive terms, the second number is obtained by adding a fixed number to the first one.
${{n}^{th}}$term of A.P,
${{a}_{n}}=a+(n-1)d$
Where,
$a=$First-term
$d=$ Common difference
$n=$ number of terms
${{a}_{n}}={{n}^{th}}$term
Now let us check if the above equation is A.P or not.
So for that common difference should be the same.
So $=a-\dfrac{(a+b)}{2}=\dfrac{a-b}{2}$
and$=\dfrac{3a-b}{2}-a=\dfrac{a-b}{2}$
Since the difference is common the series is A.P.
Now we know for the A.P sum of${{n}^{th}}$the term is,
$S=\dfrac{n}{2}\left( 2a+(n-1)d \right)$
So we want to find the sum of the first $21$terms.
So we get,
$a=\dfrac{a+b}{2},d=\dfrac{a-b}{2},n=21$.
So now substituting above values we get,
\[\begin{align}
& {{S}_{21}}=\dfrac{21}{2}\left( 2\left( \dfrac{a+b}{2} \right)+(21-1)\left( \dfrac{a-b}{2} \right) \right) \\
& {{S}_{21}}=\dfrac{21}{2}\left( \left( a+b \right)+(20)\left( \dfrac{a-b}{2} \right) \right) \\
& {{S}_{21}}=\dfrac{21}{2}\left( \left( a+b \right)+(10)\left( a-b \right) \right) \\
& {{S}_{21}}=\dfrac{21}{2}\left( \left( a+b \right)+10a-10b \right) \\
& {{S}_{21}}=\dfrac{21}{2}\left( 11a-9b \right) \\
\end{align}\]
So the sum of $\dfrac{a+b}{2},a,\dfrac{3a-b}{2},.......$ upto $21$terms is \[\dfrac{21}{2}\left( 11a-9b \right)\].
Note: Read the question carefully. If it is mentioned in the question that the series is in A.P then use the sum of first $n$ terms. If not then it is your work to check whether it is in A.P or not. Students make many mistakes in finding the sum of terms. Sometimes the terms are missing so take care of that. You should know the formula of the first $n$terms of A.P $S=\dfrac{n}{2}\left( 2a+(n-1)d \right)$.
Complete step-by-step answer:
Arithmetic Progression (A.P) is a sequence of numbers in a particular order. If we observe in our regular lives, we come across progression quite often. For example, roll numbers of a class, days in a week, or months in a year. This pattern of series and sequences has been generalized in maths as progressions. Let us learn here AP definition, important terms such as common difference, the first term of the series, nth term and sum of nth term formulas along with solved questions based on them.
It is a mathematical sequence in which the difference between two consecutive terms is always a constant and it is abbreviated as A.P.
The fixed number that must be added to any term of an A.P to get the next term is known as the common difference of the A.P.
An arithmetic sequence or progression is defined as a sequence of numbers in which for every pair of consecutive terms, the second number is obtained by adding a fixed number to the first one.
${{n}^{th}}$term of A.P,
${{a}_{n}}=a+(n-1)d$
Where,
$a=$First-term
$d=$ Common difference
$n=$ number of terms
${{a}_{n}}={{n}^{th}}$term
Now let us check if the above equation is A.P or not.
So for that common difference should be the same.
So $=a-\dfrac{(a+b)}{2}=\dfrac{a-b}{2}$
and$=\dfrac{3a-b}{2}-a=\dfrac{a-b}{2}$
Since the difference is common the series is A.P.
Now we know for the A.P sum of${{n}^{th}}$the term is,
$S=\dfrac{n}{2}\left( 2a+(n-1)d \right)$
So we want to find the sum of the first $21$terms.
So we get,
$a=\dfrac{a+b}{2},d=\dfrac{a-b}{2},n=21$.
So now substituting above values we get,
\[\begin{align}
& {{S}_{21}}=\dfrac{21}{2}\left( 2\left( \dfrac{a+b}{2} \right)+(21-1)\left( \dfrac{a-b}{2} \right) \right) \\
& {{S}_{21}}=\dfrac{21}{2}\left( \left( a+b \right)+(20)\left( \dfrac{a-b}{2} \right) \right) \\
& {{S}_{21}}=\dfrac{21}{2}\left( \left( a+b \right)+(10)\left( a-b \right) \right) \\
& {{S}_{21}}=\dfrac{21}{2}\left( \left( a+b \right)+10a-10b \right) \\
& {{S}_{21}}=\dfrac{21}{2}\left( 11a-9b \right) \\
\end{align}\]
So the sum of $\dfrac{a+b}{2},a,\dfrac{3a-b}{2},.......$ upto $21$terms is \[\dfrac{21}{2}\left( 11a-9b \right)\].
Note: Read the question carefully. If it is mentioned in the question that the series is in A.P then use the sum of first $n$ terms. If not then it is your work to check whether it is in A.P or not. Students make many mistakes in finding the sum of terms. Sometimes the terms are missing so take care of that. You should know the formula of the first $n$terms of A.P $S=\dfrac{n}{2}\left( 2a+(n-1)d \right)$.
Recently Updated Pages
Assertion The resistivity of a semiconductor increases class 13 physics CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
How do you arrange NH4 + BF3 H2O C2H2 in increasing class 11 chemistry CBSE
Is H mCT and q mCT the same thing If so which is more class 11 chemistry CBSE
What are the possible quantum number for the last outermost class 11 chemistry CBSE
Is C2 paramagnetic or diamagnetic class 11 chemistry CBSE
Trending doubts
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Difference Between Plant Cell and Animal Cell
Select the word that is correctly spelled a Twelveth class 10 english CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
What is the z value for a 90 95 and 99 percent confidence class 11 maths CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
What organs are located on the left side of your body class 11 biology CBSE
What is BLO What is the full form of BLO class 8 social science CBSE
Change the following sentences into negative and interrogative class 10 english CBSE