# Find the probability of having 5 Sundays in the month of February in leap year.

$

A.{\text{ }}\dfrac{2}{7} \\

B.{\text{ 0}} \\

{\text{C}}{\text{. }}\dfrac{1}{7} \\

D.{\text{ 1}} \\

$

Last updated date: 20th Mar 2023

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Total views: 306k

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Answer

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306k+ views

Hint:

In order to solve this question, we must know the basic approach of theoretical probability. Theoretical probability is a method to express the likelihood that something will occur. It is calculated by dividing the number of favourable outcomes by the total possible outcomes.

Complete step-by-step answer:

We know that,

There are 29 days in a leap year

No. of days in a week = 7 days

When we convert into weeks. We get that February has 4 weeks and 1 odd day

$\therefore $ 4 week = 7 $ \times $4 = 28 days

$\therefore $ 29 – 28 = 1 day is remaining.

This one day may be (Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday)

If the remaining day is Sunday, then there are 5 Sundays in February.

The required probability = $\dfrac{1}{7}$

$\therefore $ The probability of having 5 Sundays in the month of February in leap year = $\dfrac{1}{7}$

Note: –

Whenever we face such types of questions, the key concept is that we have to use the approach of theoretical probability that is determined on the basis of the likelihood of the occurrences of the given event. The probability value is expressed between the range of 0 to 1. We have to use the approach of the theory of probability then we can find the probability of the occurrence of an event like we did in the question.

In order to solve this question, we must know the basic approach of theoretical probability. Theoretical probability is a method to express the likelihood that something will occur. It is calculated by dividing the number of favourable outcomes by the total possible outcomes.

Complete step-by-step answer:

We know that,

There are 29 days in a leap year

No. of days in a week = 7 days

When we convert into weeks. We get that February has 4 weeks and 1 odd day

$\therefore $ 4 week = 7 $ \times $4 = 28 days

$\therefore $ 29 – 28 = 1 day is remaining.

This one day may be (Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday)

If the remaining day is Sunday, then there are 5 Sundays in February.

The required probability = $\dfrac{1}{7}$

$\therefore $ The probability of having 5 Sundays in the month of February in leap year = $\dfrac{1}{7}$

Note: –

Whenever we face such types of questions, the key concept is that we have to use the approach of theoretical probability that is determined on the basis of the likelihood of the occurrences of the given event. The probability value is expressed between the range of 0 to 1. We have to use the approach of the theory of probability then we can find the probability of the occurrence of an event like we did in the question.

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