Answer
384.3k+ views
Hint: We first explain the concept of median and the differences for discrete data and continuous data. The fixed number of inputs makes the median similar toa average of the numbers.
Complete step by step solution:
It is mentioned here that we are finding the median between two numbers.
Two fixed numbers mean we have been dealing with discrete data.
In case of discrete data, the Median is the number in an ordered series midway between the range extremes.
We arrange the values and find the middle value of them. For a set of only two values, the median will be the same as the mean, or arithmetic average.
In general, we have to rearrange the numbers in order from lowest to highest.
When there are an odd number of values, we can just find the value so that there are the same number of values above as there are below this middle value. When there is an even number of values, there is an issue in there is not one number that acts as a middle value. Instead, the two middle numbers such that there are the same number of values above as below these two middle numbers. As a compromise, we take the average of these two middle numbers.
For example: If we take 8 and 10 the median will be $\dfrac{8+10}{2}=\dfrac{18}{2}=9$.
Note:
Usually the average is very different from the mean or average. The median is more shifted towards the middle of the number of values irrespective of the difference between numbers and their individual values.
Complete step by step solution:
It is mentioned here that we are finding the median between two numbers.
Two fixed numbers mean we have been dealing with discrete data.
In case of discrete data, the Median is the number in an ordered series midway between the range extremes.
We arrange the values and find the middle value of them. For a set of only two values, the median will be the same as the mean, or arithmetic average.
In general, we have to rearrange the numbers in order from lowest to highest.
When there are an odd number of values, we can just find the value so that there are the same number of values above as there are below this middle value. When there is an even number of values, there is an issue in there is not one number that acts as a middle value. Instead, the two middle numbers such that there are the same number of values above as below these two middle numbers. As a compromise, we take the average of these two middle numbers.
For example: If we take 8 and 10 the median will be $\dfrac{8+10}{2}=\dfrac{18}{2}=9$.
Note:
Usually the average is very different from the mean or average. The median is more shifted towards the middle of the number of values irrespective of the difference between numbers and their individual values.
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