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# Find the length of the hypotenuse of a right triangle with legs of lengths 5 and 12 ?

Last updated date: 19th Jul 2024
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Hint: Pythagoras theorem: For a right angled triangle the square of the hypotenuse is equal to the sum of the squares of the other two sides.

So on applying Pythagoras theorem to the above triangle we can write:
${a^2} + {b^2} = {c^2} \\ \Rightarrow {c^2} = {a^2} + {b^2} \\$
Also we can find the hypotenuse of the triangle by the equation:
$c = \sqrt {{a^2} + {b^2}}$
So by using the above equation and substituting the values $a\;{\text{and}}\;b$ we can find the value of the hypotenuse.

Complete step by step solution:
Given
Legs of lengths 5 and 12
$\Rightarrow a = 5\;{\text{and}}\;b = 12..........................\left( i \right)$
Now using this value we can draw a right angled triangle as below:

Now we need to find the hypotenuse such that we need to find the value of $c$:
So on applying Pythagoras theorem to the above triangle we can write:
${a^2} + {b^2} = {c^2} \\ \Rightarrow {c^2} = {a^2} + {b^2} \\$
Now in order to find the value of$c$we need to take root of the LHS:
$c = \sqrt {{a^2} + {b^2}} .............................\left( {ii} \right)$
Now we have the values: $a = 5\;{\text{and}}\;b = 12$
Substituting the above values in (ii) we can write:
$c = \sqrt {{a^2} + {b^2}} \\ \Rightarrow c = \sqrt {{{\left( 5 \right)}^2} + {{\left( {12} \right)}^2}} \\ \Rightarrow c = \sqrt {25 + 144} \\ \Rightarrow c = \sqrt {169} \\ \Rightarrow c = 13 \\$
Therefore length of the hypotenuse of a right triangle with legs of lengths $5\;{\text{and}}\;{\text{1}}2\;{\text{is}}\;13$.

Also in a right angled triangle the sum of the three angles is ${180^ \circ }$.