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# How do you find the intercepts for $y = - 3x + 6$ ?

Last updated date: 13th Jun 2024
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Hint: The equation of a line can be written in various ways like slope-intercept form, intercept form etc. the x-intercept of a line is a point on the x-axis at which the line cuts the x-axis and the y-intercept is defined as a point on which the line cuts the y-axis. In this question, we are given a linear equation that represents the equation of a line in the x-y plane and we have to find the x and y intercepts of this equation. We will first convert the given equation into the intercept form and then compare them. The given line is a straight line and all the points lying on the line will satisfy its equation.

Complete step by step solution:
The equation of the line given to us is $y = - 3x + 6$ .It can be rewritten as –
$3x + y = 6$ .
We will convert this equation into the standard equation of x and y-intercept form as follows –
$\dfrac{{3x}}{6} + \dfrac{y}{6} = 1 \\ \Rightarrow \dfrac{x}{2} + \dfrac{y}{6} = 1 \\$
On comparing this equation with the standard equation of x and y-intercept form $\dfrac{x}{a} + \dfrac{y}{b} = 1$ ,
We get –
$a = 2$ and $b = 6$

Hence the x-intercept of the given equation is 2, and the intercept of this equation is 6.

Note: We can find out the x and y intercepts of the line from its equation. The intercept form of the equation of a line is $\dfrac{x}{a} + \dfrac{y}{b} = 1$ where a is the x-intercept of this line ad b is the y-intercept of the line. We can also find the x and y intercepts by putting the other point equal to zero. This way we can solve similar questions.