
Find the area of a sector of a circle with radius 6 cm if the angle of the sector is $60^\circ $.
Answer
511.2k+ views
Hint: We need to multiply the square of the radius with $\pi = \dfrac{{22}}{7}$ to get the area of the circle. This area of the circle is multiplied with the quotient obtained on dividing $60^\circ $ by $360^\circ $ to get the area of the sector of a circle.
Complete step-by-step solution
We are given a circle with radius 6 cm.
Also, we are given that the angle of a sector of this circle is $60^\circ $.
We are asked to compute the area of this sector of the circle.
Let’s have a look at the figure of this circle.
The shaded portion is the sector for which we are to find the area.
If the angle $\theta $measured in degrees, then the area of the sector of the circle is given by the formula
Area of sector\[ = \dfrac{\theta }{{360^\circ }} \times \pi {r^2}\]
Where r is the length of the radius of the circle and $\theta $ is the angle of the sector.
We have$\theta = 60^\circ $ and $r = 6cm$. Take$\pi = \dfrac{{22}}{7}$.
Therefore, on substituting, we get
Area of sector\[ = \dfrac{{60^\circ }}{{360^\circ }} \times \dfrac{{22}}{7} \times {6^2} = \dfrac{{22}}{7} \times 6 \approx 18.86c{m^2}\]
Hence the required area is \[18.86c{m^2}\].
Note:Students tend to use the formula for area of sector wrongly. Instead of $\pi {r^2}$, they tend to use$2\pi r$in the formula. This will give you the length of the arc and not the area of the sector because $2\pi r$ is the length of the circumference of the circle.
Complete step-by-step solution
We are given a circle with radius 6 cm.
Also, we are given that the angle of a sector of this circle is $60^\circ $.
We are asked to compute the area of this sector of the circle.
Let’s have a look at the figure of this circle.
The shaded portion is the sector for which we are to find the area.
If the angle $\theta $measured in degrees, then the area of the sector of the circle is given by the formula
Area of sector\[ = \dfrac{\theta }{{360^\circ }} \times \pi {r^2}\]
Where r is the length of the radius of the circle and $\theta $ is the angle of the sector.
We have$\theta = 60^\circ $ and $r = 6cm$. Take$\pi = \dfrac{{22}}{7}$.
Therefore, on substituting, we get
Area of sector\[ = \dfrac{{60^\circ }}{{360^\circ }} \times \dfrac{{22}}{7} \times {6^2} = \dfrac{{22}}{7} \times 6 \approx 18.86c{m^2}\]
Hence the required area is \[18.86c{m^2}\].
Note:Students tend to use the formula for area of sector wrongly. Instead of $\pi {r^2}$, they tend to use$2\pi r$in the formula. This will give you the length of the arc and not the area of the sector because $2\pi r$ is the length of the circumference of the circle.
Recently Updated Pages
Master Class 12 Biology: Engaging Questions & Answers for Success

Class 12 Question and Answer - Your Ultimate Solutions Guide

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Trending doubts
Which are the Top 10 Largest Countries of the World?

Why is insulin not administered orally to a diabetic class 12 biology CBSE

a Tabulate the differences in the characteristics of class 12 chemistry CBSE

Why is the cell called the structural and functional class 12 biology CBSE

The total number of isomers considering both the structural class 12 chemistry CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
