
How do you find the antiderivative of \[{{\left( 5x+1 \right)}^{2}}\] ?
Answer
527.4k+ views
Hint: For the given question we are given to solve the antiderivative of \[{{\left( 5x+1 \right)}^{2}}\]. For that let us expand the given equation by using basic algebraic formulas and then we have to integrate the resultant equation by using the basic integration formulas.
Complete step by step answer:
For the given problem we are given to find the antiderivative of the equation \[{{\left( 5x+1 \right)}^{2}}\].
Let us consider the given equation as equation (1) to get solved.
\[a={{\left( 5x+1 \right)}^{2}}...........\left( 1 \right)\]
For a polynomial of just degree 2, I would expand the equation and solve.
So, let us expand the equation (1) by using the formula \[{{\left( a+b \right)}^{2}}={{a}^{2}}+2ab+{{b}^{2}}\].
Let us consider the given formula as formula (f1).
\[{{\left( a+b \right)}^{2}}={{a}^{2}}+2ab+{{b}^{2}}............\left( f1 \right)\]
By using the formula (f1) let us expand equation (1)
\[\Rightarrow a=25{{x}^{2}}+1+10x\]
Let us consider the above equation as equation (2).
\[\Rightarrow a=25{{x}^{2}}+1+10x................\left( 2 \right)\]
By doing antiderivative to the equation (2).
\[\Rightarrow a=\int{25{{x}^{2}}+1+10x\text{ dx}}\]
Let us consider the given equation as equation (2).
\[\Rightarrow a=\int{25{{x}^{2}}+1+10x\text{ dx}}...............\left( 2 \right)\]
As we know the formula \[\int{{{a}^{x}}dx=\dfrac{{{a}^{x+1}}}{x+1}+c}\].
Let us consider the above formula as (f2).
\[\int{{{a}^{x}}dx=\dfrac{{{a}^{x+1}}}{x+1}+c}................\left( 2 \right)\]
By applying formula (f2) to equation (2), we get
\[\Rightarrow a=25\dfrac{{{x}^{3}}}{3}+x+10\dfrac{{{x}^{2}}}{2}\]
By simplifying a bit, we get
\[\Rightarrow a=\dfrac{25}{3}{{x}^{3}}+x+5{{x}^{2}}+c\]
By arranging terms in power wise, we get
\[\Rightarrow a=\dfrac{25}{3}{{x}^{3}}+5{{x}^{2}}+x+c\]
Therefore, let us consider the equation as equation (3).
\[\Rightarrow a=\dfrac{25}{3}{{x}^{3}}+x+5{{x}^{2}}+c...............\left( 3 \right)\]
Therefore, antiderivative of \[{{\left( 5x+1 \right)}^{2}}\] is \[a=\dfrac{25}{3}{{x}^{3}}+5{{x}^{2}}+x+c\].
Note:
We should know that antiderivative means summation i.e. integration. We can do this problem by another way i.e. we can do direct integration to the given equation without expanding. But I think the way I solved this problem is easier than any other method.
Complete step by step answer:
For the given problem we are given to find the antiderivative of the equation \[{{\left( 5x+1 \right)}^{2}}\].
Let us consider the given equation as equation (1) to get solved.
\[a={{\left( 5x+1 \right)}^{2}}...........\left( 1 \right)\]
For a polynomial of just degree 2, I would expand the equation and solve.
So, let us expand the equation (1) by using the formula \[{{\left( a+b \right)}^{2}}={{a}^{2}}+2ab+{{b}^{2}}\].
Let us consider the given formula as formula (f1).
\[{{\left( a+b \right)}^{2}}={{a}^{2}}+2ab+{{b}^{2}}............\left( f1 \right)\]
By using the formula (f1) let us expand equation (1)
\[\Rightarrow a=25{{x}^{2}}+1+10x\]
Let us consider the above equation as equation (2).
\[\Rightarrow a=25{{x}^{2}}+1+10x................\left( 2 \right)\]
By doing antiderivative to the equation (2).
\[\Rightarrow a=\int{25{{x}^{2}}+1+10x\text{ dx}}\]
Let us consider the given equation as equation (2).
\[\Rightarrow a=\int{25{{x}^{2}}+1+10x\text{ dx}}...............\left( 2 \right)\]
As we know the formula \[\int{{{a}^{x}}dx=\dfrac{{{a}^{x+1}}}{x+1}+c}\].
Let us consider the above formula as (f2).
\[\int{{{a}^{x}}dx=\dfrac{{{a}^{x+1}}}{x+1}+c}................\left( 2 \right)\]
By applying formula (f2) to equation (2), we get
\[\Rightarrow a=25\dfrac{{{x}^{3}}}{3}+x+10\dfrac{{{x}^{2}}}{2}\]
By simplifying a bit, we get
\[\Rightarrow a=\dfrac{25}{3}{{x}^{3}}+x+5{{x}^{2}}+c\]
By arranging terms in power wise, we get
\[\Rightarrow a=\dfrac{25}{3}{{x}^{3}}+5{{x}^{2}}+x+c\]
Therefore, let us consider the equation as equation (3).
\[\Rightarrow a=\dfrac{25}{3}{{x}^{3}}+x+5{{x}^{2}}+c...............\left( 3 \right)\]
Therefore, antiderivative of \[{{\left( 5x+1 \right)}^{2}}\] is \[a=\dfrac{25}{3}{{x}^{3}}+5{{x}^{2}}+x+c\].
Note:
We should know that antiderivative means summation i.e. integration. We can do this problem by another way i.e. we can do direct integration to the given equation without expanding. But I think the way I solved this problem is easier than any other method.
Recently Updated Pages
Master Class 11 Chemistry: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

How many 5 digit telephone numbers can be constructed class 11 maths CBSE

Draw a well labelled diagram of reflex arc and explain class 11 biology CBSE

What is the difference between noise and music Can class 11 physics CBSE

Trending doubts
1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

1 ton equals to A 100 kg B 1000 kg C 10 kg D 10000 class 11 physics CBSE

Draw a diagram showing the external features of fish class 11 biology CBSE

What is the z value for a 90 95 and 99 percent confidence class 11 maths CBSE

Earth rotates in which direction A East to west B West class 11 physics CBSE

