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Hint: - Probability is equal to the ratio of number of outcomes to total possible outcomes.

According to the question, we have given that ${\text{A}}{\text{.}}$ The pointer can stop at one of the following regions$A,A,D,B,C$ .

But if we can recall we will find that only in the $1$ case, the pointer will stop at D.

So, probability for this case will be

$P = \dfrac{1}{5}$

\[{\text{B}}{\text{.}}\] We all know that there are $52$ cards:

We have $4$ ace cards over $52$ cards,

So, probability of getting an ace card

$ \Rightarrow \dfrac{4}{{52}} = \dfrac{1}{{13}}$

\[{\text{C}}{\text{.}}\]There are a total of $7$ apples, out of which $4$ are red and $3$ are green.

Probability of red apple $ \Rightarrow \dfrac{4}{7}$

Note – Probability can never be greater than 1 nor it can be less than 0. In this type of question only

smart thinking is required. A deck of cards has $52$mainly $4$ sets each of $13$ cards i.e

spades,clubs,diamonds and hearts. Probability is equal to the ratio of number of outcomes to total

number of outcomes.

According to the question, we have given that ${\text{A}}{\text{.}}$ The pointer can stop at one of the following regions$A,A,D,B,C$ .

But if we can recall we will find that only in the $1$ case, the pointer will stop at D.

So, probability for this case will be

$P = \dfrac{1}{5}$

\[{\text{B}}{\text{.}}\] We all know that there are $52$ cards:

We have $4$ ace cards over $52$ cards,

So, probability of getting an ace card

$ \Rightarrow \dfrac{4}{{52}} = \dfrac{1}{{13}}$

\[{\text{C}}{\text{.}}\]There are a total of $7$ apples, out of which $4$ are red and $3$ are green.

Probability of red apple $ \Rightarrow \dfrac{4}{7}$

Note – Probability can never be greater than 1 nor it can be less than 0. In this type of question only

smart thinking is required. A deck of cards has $52$mainly $4$ sets each of $13$ cards i.e

spades,clubs,diamonds and hearts. Probability is equal to the ratio of number of outcomes to total

number of outcomes.

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