
Find and correct errors of the following mathematical expressions:
$2x+3y=5xy$
Answer
510.9k+ views
Hint:Use the left hand side and the right hand side equalization through
Mathematical operation
Use BODMAS rule for mathematical operation
Complete step by step solution:
Error is the mistake in the question where after applying mathematical operation
or by simplifying we could not reach at equality of left hand side and right hand
side .
we can find the mistake in the question part after verifying it and that mistake term
will be regarded as errors for the given expressions.
Here we will use BODMAS rule
Which stands :
B is bracket
O is of
D is division
M is multiplication
A is addition
S is subtraction
Their symbols :
For bracket we have three parts
Small bracket is denoted as $\left( {} \right)$
Middle bracket is denoted as $\left\{ {} \right\}$
Big bracket is denoted as $\left[ {} \right]$
O is denoted as of
Division is denoted as $\div $
Multiplication is denoted as $\times $
Addition is denoted as $+$
Subtraction us denoted as $-$
This BODMAS is used as per the following guidelines
Whenever we will see these operation simultaneously we will apply
First operation acceding to the first letter of BODMAS
Which means the correct order for this rule is
Bracket
Of
Division
Multiplication
Addition then
Subtraction
Given expression is $2x+3y=5xy$
We can also write it $2x+3y-5xy=0$
Here there are two operation addition and subtraction so according to
BODMAS we apply addition first after that subtraction
In this condition $2x+3y$ cannot be added as it is not same type of terms
Thus, the expression will remain as $2x+3y=5xy$
Here in left hand side it is $2x+3y$ and in right hand side it is $5xy$
Thus it is not satisfying both sides
Hence correct error is $2x+3y=5xy$
Note:If we move any terms from right side to left side then their sign get change
Suppose positive sign is at right side then negative sign will be at left side.Modify the equation accordingly and solve it.
Mathematical operation
Use BODMAS rule for mathematical operation
Complete step by step solution:
Error is the mistake in the question where after applying mathematical operation
or by simplifying we could not reach at equality of left hand side and right hand
side .
we can find the mistake in the question part after verifying it and that mistake term
will be regarded as errors for the given expressions.
Here we will use BODMAS rule
Which stands :
B is bracket
O is of
D is division
M is multiplication
A is addition
S is subtraction
Their symbols :
For bracket we have three parts
Small bracket is denoted as $\left( {} \right)$
Middle bracket is denoted as $\left\{ {} \right\}$
Big bracket is denoted as $\left[ {} \right]$
O is denoted as of
Division is denoted as $\div $
Multiplication is denoted as $\times $
Addition is denoted as $+$
Subtraction us denoted as $-$
This BODMAS is used as per the following guidelines
Whenever we will see these operation simultaneously we will apply
First operation acceding to the first letter of BODMAS
Which means the correct order for this rule is
Bracket
Of
Division
Multiplication
Addition then
Subtraction
Given expression is $2x+3y=5xy$
We can also write it $2x+3y-5xy=0$
Here there are two operation addition and subtraction so according to
BODMAS we apply addition first after that subtraction
In this condition $2x+3y$ cannot be added as it is not same type of terms
Thus, the expression will remain as $2x+3y=5xy$
Here in left hand side it is $2x+3y$ and in right hand side it is $5xy$
Thus it is not satisfying both sides
Hence correct error is $2x+3y=5xy$
Note:If we move any terms from right side to left side then their sign get change
Suppose positive sign is at right side then negative sign will be at left side.Modify the equation accordingly and solve it.
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