Answer
Verified
409.5k+ views
Hint: First write the equation of motion of each block. Take into consideration the tension produced in the string, weight (mg) component along the inclined plane.
TENSION: whenever any string is tight then the end of the string pulls whatever is connected to them in inward direction. This inward pulling force of the string on the object is called a tension force. It depends on mass, as mass increases tension also increases.
Remember that the heavy block will move down and the light block will slide up. According to this, it gives direction to the acceleration produced.
Complete step by step answer
Let T, be the tension produced in the string and ‘a’ be the acceleration produced in each block.
Therefore, equation of motion of block A can be written as
$ \begin{align}
& {{m}_{A}}g\sin \theta -T={{m}_{A}}a \\
& {{m}_{A}}g\sin 37{}^\circ -T={{m}_{A}}a\text{ }............\text{(1)} \\
& \text{Equation of motion for block B is:-} \\
& T-{{m}_{B}}g\sin {{\theta }_{2}}={{m}_{B}}a\text{ } \\
& T-{{m}_{B}}g\sin 53{}^\circ ={{m}_{B}}a\text{ }.............\text{(2)} \\
\end{align} $
Adding equations 1. and 2. Gives,
$ \begin{align}
& g({{m}_{A}}\sin 37{}^\circ -{{m}_{b}}\sin 53{}^\circ )=({{m}_{A}}+{{m}_{B}})a \\
& g(100\times \dfrac{3}{5}-50\times \dfrac{4}{5})=(100+50)a \\
& 10(60-40)=150a \\
& a=\dfrac{200}{15}=\dfrac{4}{3}m/{{s}^{2}} \\
& \text{Thus acceleration of block= 4/3 ms}_{^{{}}}^{-2} \\
\end{align} $ .
Additional Information
Consider the situation as given in the following diagram.
$ \begin{align}
& Here,\angle LMN=\angle BAC=\theta \\
& \\
\end{align} $
Because, the angle between the two lines is equal to the angle between the normal of that line.
$ \text{As here, MN}\bot \text{AC and BA}\bot \text{AD} $
Thus component along AN = mg $ \text{sin }\!\!\theta\!\!\text{ } $
Component along AB = mg $ \text{cos }\!\!\theta\!\!\text{ } $ .
Note
Equations 1 and 2 are taken according to the direction of acceleration produced in each block. Thus taking into account which force is dominant, according to which large value of force is to be subtracted from the small value, to get the resultant force.
Remember that the second law of Newton states that the acceleration of an object is dependent upon two variables - the net force acting upon the object and the mass of the object.
TENSION: whenever any string is tight then the end of the string pulls whatever is connected to them in inward direction. This inward pulling force of the string on the object is called a tension force. It depends on mass, as mass increases tension also increases.
Remember that the heavy block will move down and the light block will slide up. According to this, it gives direction to the acceleration produced.
Complete step by step answer
Let T, be the tension produced in the string and ‘a’ be the acceleration produced in each block.
Therefore, equation of motion of block A can be written as
$ \begin{align}
& {{m}_{A}}g\sin \theta -T={{m}_{A}}a \\
& {{m}_{A}}g\sin 37{}^\circ -T={{m}_{A}}a\text{ }............\text{(1)} \\
& \text{Equation of motion for block B is:-} \\
& T-{{m}_{B}}g\sin {{\theta }_{2}}={{m}_{B}}a\text{ } \\
& T-{{m}_{B}}g\sin 53{}^\circ ={{m}_{B}}a\text{ }.............\text{(2)} \\
\end{align} $
Adding equations 1. and 2. Gives,
$ \begin{align}
& g({{m}_{A}}\sin 37{}^\circ -{{m}_{b}}\sin 53{}^\circ )=({{m}_{A}}+{{m}_{B}})a \\
& g(100\times \dfrac{3}{5}-50\times \dfrac{4}{5})=(100+50)a \\
& 10(60-40)=150a \\
& a=\dfrac{200}{15}=\dfrac{4}{3}m/{{s}^{2}} \\
& \text{Thus acceleration of block= 4/3 ms}_{^{{}}}^{-2} \\
\end{align} $ .
Additional Information
Consider the situation as given in the following diagram.
$ \begin{align}
& Here,\angle LMN=\angle BAC=\theta \\
& \\
\end{align} $
Because, the angle between the two lines is equal to the angle between the normal of that line.
$ \text{As here, MN}\bot \text{AC and BA}\bot \text{AD} $
Thus component along AN = mg $ \text{sin }\!\!\theta\!\!\text{ } $
Component along AB = mg $ \text{cos }\!\!\theta\!\!\text{ } $ .
Note
Equations 1 and 2 are taken according to the direction of acceleration produced in each block. Thus taking into account which force is dominant, according to which large value of force is to be subtracted from the small value, to get the resultant force.
Remember that the second law of Newton states that the acceleration of an object is dependent upon two variables - the net force acting upon the object and the mass of the object.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
Mark and label the given geoinformation on the outline class 11 social science CBSE
When people say No pun intended what does that mea class 8 english CBSE
Name the states which share their boundary with Indias class 9 social science CBSE
Give an account of the Northern Plains of India class 9 social science CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Trending doubts
Difference Between Plant Cell and Animal Cell
In Indian rupees 1 trillion is equal to how many c class 8 maths CBSE
Which are the Top 10 Largest Countries of the World?
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
How do you graph the function fx 4x class 9 maths CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths