
Filament of torch bulb is?
A. A metal case
B. Metal tip at the center of the base
C. 2 thick wires
D. Thin wires.
Answer
593.4k+ views
Hint: - When an electric current is passed through a conductor, it generates heat.
- For an electric bulb, we use heat to generate light.
- Heat is generated according to Joule’s law of heating.
- More resistance means more heat.
- Again, resistance is inversely proportional to the cross-sectional area of the wire.
Complete step by step solution:
The filament of the torch bulb should be a conductor. That’s why when the current will pass through it, it will generate heat. And from that heat energy light will be generated.
According to Joule’s law of heating,
The heat generated at any resistance, \[H = {I^2}Rt\]
Where $I$ is the current through the resistance $R$ and $t$ is the time.
Again, $R = \rho \dfrac{L}{A}$ where$R$ is the resistivity of the material, $L$ is the length of the wire and $A$ is the cross-sectional area of the wire.
So, to generate more heat energy resistance should be more and to get more resistance cross-sectional area of the wire should be less.
So, to get more heat we should use a thin wire.
The filament of the torch bulb is a thin wire.
The correct option is (D).
Note:
- Same concept works for electric iron or electric heaters or electric fuses also.
- And to create more resistance the length of the wire should me more. That’s why the filament has a spiral (spring-like) shape.
- Basically, filament is a very thin spiral wire.
- For an electric bulb, we use heat to generate light.
- Heat is generated according to Joule’s law of heating.
- More resistance means more heat.
- Again, resistance is inversely proportional to the cross-sectional area of the wire.
Complete step by step solution:
The filament of the torch bulb should be a conductor. That’s why when the current will pass through it, it will generate heat. And from that heat energy light will be generated.
According to Joule’s law of heating,
The heat generated at any resistance, \[H = {I^2}Rt\]
Where $I$ is the current through the resistance $R$ and $t$ is the time.
Again, $R = \rho \dfrac{L}{A}$ where$R$ is the resistivity of the material, $L$ is the length of the wire and $A$ is the cross-sectional area of the wire.
So, to generate more heat energy resistance should be more and to get more resistance cross-sectional area of the wire should be less.
So, to get more heat we should use a thin wire.
The filament of the torch bulb is a thin wire.
The correct option is (D).
Note:
- Same concept works for electric iron or electric heaters or electric fuses also.
- And to create more resistance the length of the wire should me more. That’s why the filament has a spiral (spring-like) shape.
- Basically, filament is a very thin spiral wire.
Recently Updated Pages
Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

